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aniked [119]
2 years ago
9

Inequalities Word Problem:

Mathematics
1 answer:
OLEGan [10]2 years ago
3 0

Answer:

37.5 hours.

Step-by-step explanation:

750-300=450

450/12= 37.5

Liza needs to work 37.5 hours.

To check work:

37.5*12=450

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AfilCa [17]

Answer:

it is C

Step-by-step explanation:

4 0
2 years ago
PLEASE HELP ASAP
Leno4ka [110]

Answer:

x=10

Step-by-step explanation:

we know that

If the lines m and n are parallel

then

130\° = (8x+50)\° ----> by corresponding angles

solve for x

8x=130-50\\8x=80\\x=10

7 0
3 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

                        p = \frac{70}{100} = 0.7  

Let P(a vehicle not passing the test) = q

                         q = 1 - p

                         q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

                           = 0.7 × 0.7 × 0.7

                           = 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

      = (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

      = 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

      = 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

                 = 0.063 + 0.063 + 0.063

                 = 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

                 = 0.063 + 0.063 + 0.063 + 0.027

                 = 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

=  (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

                  = 0.973  

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

                         = \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}

                         = \frac{0.343}{0.973}

                         = 0.353

3 0
3 years ago
Read 2 more answers
Pls help. No files pls. Will give brainliest.
nordsb [41]

To find f(-20), first figure out which piece x = -20 fits with.

Since -20 < -12, x = -20 first in the domain used by the third piece.

For f(-20), treat this function as if it was just f(x) = 3x-7.

f(-20) = 3(-20) -7

         = -60 - 7

         = -67

6 0
2 years ago
There are 360 boys in green valley elementary school elementary school there are 180 there are 180 more boys then girls
HACTEHA [7]
Your answer to this problem is 180 girls in green valley elementary school.
8 0
3 years ago
Read 2 more answers
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