Yes, you are right. the length is 3, the height is 2, and the width is 1
Given:
Cards labelled 1, 3, 5, 6, 8 and 9.
A card is drawn and not replaced. Then a second card is drawn at random.
To find:
The probability of drawing 2 even numbers.
Solution:
We have,
Even number cards = 6, 8
Odd numbers cards = 1, 3, 5, 9
Total cards = 1, 3, 5, 6, 8 and 9
Number of even cards = 2
Number of total cards = 6
So, the probability of getting an even card in first draw is:
Now,
Number of remaining even cards = 1
Number of remaining cards = 5
So, the probability of getting an even card in second draw is:
The probability of drawing 2 even numbers is:
Therefore, the probability of drawing 2 even numbers is 
. Hence, the correct option is (b).
Answer:
Hi I only know part be yes the figures are congruent
Step-by-step explanation:
There the same shape, same size so yes they are congruent
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
P(brown) = 12% = 0.12
P(Yellow) = 15% = 0.15
P(Red) = 12% = 0.12
P(blue) = 23% = 0.23
P(orange) = 23% = 0.23
P(green) = 15% = 0.15
A.) Compute the probability that a randomly selected peanut M&M is not yellow.
P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85
B.) Compute the probability that a randomly selected peanut M&M is brown or red.
P(Brown) or P(Red) :
0.12 + 0.12 = 0.24
C.) Compute the probability that three randomly selected peanut M&M’s are all brown.
P(brown) * P(brown) * P(brown)
0.12 * 0.12 * 0.12 =0.001728
D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.
P(3 blue)' = 1 - P(3 blue)
P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167
1 - P(3 blue) = 1 - 0.012167 = 0.987833
If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.
P(1 blue) + p(2 blue) + p(3 blue)
(0.23) + (0.23*0.23) + (0.23*0.23*0.23)
0.23 + 0.0529 + 0.012167
= 0.295067
Answer: on the outside .
Step-by-step explanation:
