In the diagram below of triangle EFG, H is a midpoint of EF and J is a midpoint
1 answer:
Answer:
m<HJF =
Step-by-step explanation:
From the given diagram, ΔFHJ is similar to ΔFEG. So that;
m<HJF = m<EGJ
⇒ 10x + 36 = 6x + 44
10x - 6x = -36 + 44
4x = 8
x =
x = 2
Substitute the value of x in the expression for m<HJF to have,
m<HJF = 10x + 36
= 10(2) + 36
= 20 + 36
m<HJF =
The measure of angle HJF is .
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The approximate area of the park on the grid is: E. about 40 km² to 50 km².
<h3>How to Find the Approximate Area on a Coordinate Grid?</h3>The number of square on a coordinate grid that is covered determines the area covered. We can make an estimate by counting how many of this square on the coordinate grid that is covered, then find out the area depending on how much square area each grid represents.
In the coordinate plane given, which shows a park, we are told that each of the square on the grid equals 1 k = square kilometer.
The number of each of these squares we can find that is covered by the park on the grid is: 48 squares.
Therefore, the area of 48 squares on the grid = 48 × 1 = 48 km². Since not all squares are fully covered by the park, we can state that the approximate area of the park on the grid is: E. about 40 km² to 50 km².
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