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3 years ago

The volume of a cone, V, is represented by , where r is the cone’s radius and h its height.

1 answer:

8 0

So the height will equal 95.50 inches.

So if you double the height the volume is 1800cm3 and that is double the original volume

And if you double the height the volume is 3600cm3 and that is the triple the original volume

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Heather lives 7 / 10 mile from theschool and 2 / 5 miles from the library . How much closer does Heather live to the library tha

frez [133]

First get the same denominator 2/5=4/10 so from here do 7/10-4/10 the denominator stays the same and the numerator changes, 3/10 is the answer so Heather live 3/10 of a mile closer to the library than the school

6 0

3 years ago

Can someone help me

Elan Coil [88]

The last choice because all the numbers are plotted correctly

3 0

4 years ago

(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte

Hunter-Best [27]

(a) If

f(x) = a₀ + a₁ x + a₂ x ² + a₃ x ³

then from the given conditions we get the system of equations,

f (-1) = a₀ - a₁ + a₂ - a₃ = -1

f (1) = a₀ + a₁ + a₂ + a₃ = 2

f (2) = a₀ + 2a₁ + 4a₂ + 8a₃ = 1

f (3) = a₀ + 3a₁ + 9a₂ + 27x ³ = 5

(b) Similarly, if

f(x) = a₀ + a₁ x + a₂ x ² + a₃ x ³

then

f'(x) = a₁ + 2a₂ x + 3a₃ x ²

so that the given conditions yield the system,

f (1) = a₀ + a₁ + a₂ + a₃ = 0

f' (1) = a₁ + 2a₂ + 3a₃ = 2

f (2) = a₀ + 2a₁ + 4a₂ + 27a₃ = 3

f' (2) = a₁ + 4a₂ + 12a₃ = -1

7 0

3 years ago

In August, Ralph bought a new set of golf clubs that cost $565. The cost of the clubs was marked up to $650 in October. Which pr

BartSMP [9]

The percent of the original price, the new price is given as 86.9%

Solution:

Given, In August, Ralph bought a new set of golf clubs that cost $565.

The cost of the clubs was marked up to $650 in October.

We have to find which proportion can be used to find what percent of the original price the new price is, if p represents the unknown percent?

The formula is normally partial/whole equals to percentage/100. In this case $565 is partial because the price increased.

So it will be,

$\frac{565}{650}=\frac{p}{100}$

$\begin{array}{l}{565 \times 100=p \times 650} \\\\ {650 p=56500} \\\\ {p=\frac{56500}{650}=86.9230}\end{array}$

Whenever you get results like these, you just need to round to the nearest hundredths place, which is 86.9%.

Hence, the percentage is 86.9%

5 0

3 years ago

You have 24 months left until you graduate and you plan on buying yourself a new $20,000 car on graduation day. If you invest $3

shusha [124]

Answer: No, the money won't be enough to buy the car

Step-by-step explanation:

you plan on buying yourself a new $20,000 car on graduation day and graduation day is 24 months time. If you invest $300 a month for the next 24 months.

The principal amount, p = 300

He is earning 4% a month, it means that it was compounded once in four months. This also means that it was compounded quarterly. So

n = 4

The rate at which the principal was compounded is 4%. So

r = 4/100 = 0.04

It was compounded for a total of 24 months. This is equivalent to 2 years. So

n = 2

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount that would be compounded at the end of n years.

A = 300(1 + (0.04/4)/4)^4×2

A = 300(1 + 0.01)^8

A = 300(1.01)^8

A = $324.857

The total amount at the end of 24 months is below the cost of the car which is $20000. So he won't have enough money to buy the car

3 0

4 years ago