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snow_lady [41]
3 years ago
6

63÷6 = ? ,,,,, please try to give a full solution​

Mathematics
2 answers:
fenix001 [56]3 years ago
7 0

Answer:

10.5

Step-by-step explanation:

63/6=10.5 or 10 and 1 half

mylen [45]3 years ago
4 0

Answer:

have 6 boxes and evenly distrbute one at a time in all of them, thus you're answer, 10.5

Step-by-step explanation:

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Is the equation = 0.25 + 0.5(– 2) linear or nonlinear?
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-0.75 linear

Step-by-step explanation:

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3 years ago
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Which decimal is the greatest?
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3.2591 is the greatest
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7 > z + 18 ≥ 6 please help me!
sp2606 [1]

7 > z + 18 ≥ 6

Subtract 18 from all 3 parts:

7-18 > z +18 -18 ≥ 6-18

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5 0
3 years ago
A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measurin
Ratling [72]

Answer:

The standard deviation of weight for this species of cockroaches is 4.62.

Step-by-step explanation:

Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

To find : What is the approximate standard deviation of weight for this species of cockroaches?

Solution :

We have given,

Mean \mu=50

The sample mean x=55

A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

i.e. P(X>55)=14%=0.14

The total probability needs to sum up to 1,

P(X\leq 55)=1-P(X>55)

P(X\leq 55)=1-0.14

P(X\leq 55)=0.86

The z-score value of 0.86 using z-score table is z=1.08.

Applying z-score formula,

z=\frac{x-\mu}{\sigma}

Where, \sigma is standard deviation

Substitute the values,

z=\frac{x-\mu}{\sigma}

1.08=\frac{55-50}{\sigma}

1.08=\frac{5}{\sigma}

\sigma=\frac{5}{1.08}

\sigma=4.62

The standard deviation of weight for this species of cockroaches is 4.62.

4 0
3 years ago
hello. I hope your day was fine and have some difficulties in the three question I just took a picture of please help me ​
goblinko [34]
What do you wanna find in these questions?
3 0
3 years ago
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