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Anettt [7]
3 years ago
13

232. Сколько решений имеет уравнение | х + 3 | -один?

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0

Answer: <em>уравнение имеет 2 решения:</em>

<em>               x₁ = - 4;    x₂ = - 2.</em>

Step-by-step explanation:

<em>Ix + 3I = 1</em>

<em>1) x + 3 = 1</em>

<em>   x + 3 - 3 = 1 - 3</em>

<em>   x = -2</em>

<em>2) - (x + 3) = 1</em>

<em>    x + 3 = - 1</em>

<em>    x + 3 - 3 = - 1 - 3</em>

<em>    x = - 4</em>

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Pls answer quick I will give brainliest
eimsori [14]

Answer:

EBC and CBF are supplementary.

EBD=66

Step-by-step explanation:

Since vertical angles are congruent, ABE=CBF

ABE=40-x

40-x + 6x-30=90

5x+10=90

5x=80

x=16

16(6)-30=66

6 0
3 years ago
If one pair of opposite sides of a quadrilateral is both congruent and____ then the quadrilateral is a parallelogram then the
never [62]

Answer:

parallel

a quadrilateral can be a parallelogram only and only if pair of opposite sides are equal and parallel.

5 0
1 year ago
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son4ous [18]
Answer would probably be 3
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3 years ago
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The life of light bulbs is distributed normally. The standard deviation of the lifetime is 25 hours and the mean lifetime of a b
riadik2000 [5.3K]

Answer:

0.9699 = 96.99% probability of a bulb lasting for at most 637 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 590, \sigma = 25

Find the probability of a bulb lasting for at most 637 hours.

This is the pvalue of Z when X = 637. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{637 - 590}{25}

Z = 1.88

Z = 1.88 has a pvalue of 0.9699

0.9699 = 96.99% probability of a bulb lasting for at most 637 hours.

5 0
2 years ago
A set of data contains 53 observations. The lowest value is 42 and the largest is 129. The data are to be organized into a frequ
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Answer:

53

Step-by-step explanation:

Answer: (a) Let, k is the number of classes and n is the number of observation.

So we select the class intervals such that for the smallest value of k, 2^k > n is satisfied.

Given, n = 53

6 0
3 years ago
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