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malfutka [58]
3 years ago
14

The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P

= a Superscript three-halves. If Saturn’s orbital period is 29.5 years, what is its distance from the sun?
Mathematics
1 answer:
mixas84 [53]3 years ago
7 0

Answer:

9.54731702 astronomical units

Step-by-step explanation:

P=a^{\frac{3}{2} }

Substitute this value in the equation above:

29.5=a^{\frac{3}{2} }

⇒ (29.5)^{\frac{3}{2} } =a

⇒ a=9.54731702 astronomical units

Hence, its distance from the sun is 9.54731702 astronomical units.

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