Question

The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P = a Superscript three-halves. If Saturn’s orbital period is 29.5 years, what is its distance from the sun?

Answer 1

Answer:

9.54731702 astronomical units

Step-by-step explanation:

$P=a^{\frac{3}{2} }$

Substitute this value in the equation above:

$29.5=a^{\frac{3}{2} }$

⇒ $(29.5)^{\frac{3}{2} } =a$

⇒ $a=9.54731702$ $astronomical$ $units$

Hence, its distance from the sun is 9.54731702 astronomical units.