Distributive Property: a ( b + c) = (a*b) + (a*c)
b) x(x + 9) = x*x + 9*x
= x² + 9x
c) x² - 18x
x² = x * x
18x = 18 *x
G C F = x
Greatest common factor in both the terms is 'x'.Take the common variable from both the terms.
x² - 18x = x*x - 18*x
= x (x - 18)
Standard form. Factored form
x² x*x
x² + 9x x(x +9)
x² - 18x x(x - 18)
-x² + 10x x(-x + 10) = x(10 -x)
-x² - 2.75x -x(x + 2.75)
The sum of the terms of a geometric sequence with common ratio lesser than 1 is calculated through the equation,
Sn = (a1) x (1 - r^n) / (1 - r)
Substituting the known values,
S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27
Thus, the sum of the first five terms is approximately equal to 8.96.
To prove a quadrilateral<span> is a </span>parallelogram<span>, you must use one of these five ways. </span>Prove that<span> both pairs of opposite sides </span>are<span> parallel. </span>Prove that<span> both pairs of opposite sides </span>are<span> congruent.</span>Prove that<span> one pair of opposite sides is both congruent </span>and<span> parallel. </span>Prove that<span> the diagonals bisect each other.</span>
Step-by-step explanation:
1.(4,9) & (1,6)
m=y²-y¹/x²-x¹
m=6-9/1-4
m=-3/-3
m= 1
2.(5,3) & (5,-9)
m=y²-y¹/x²-x¹
m=(-9)-3/5-5
m=-12/0
3.(2,1) & (8,9)
m=y²-y¹/x²-x¹
m=9-1/8-2
m=8/6
m= 4/3
4.(14,-8) & (7,-6)
m=y²-y¹/x²-x¹
m=(-6)-(-8)/7-14
m=2/-7
m= -2/7
5.(4,-3) & (8,-3)
m=y²-y¹/x²-x¹
m=(-3)-(-3)/8-4
m=0/4
m=0
6.(-11,1) & (-2,6)
m=y²-y¹/x²-x¹
m=6-1/(-2)-(-11)
m=5/9
