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vagabundo [1.1K]
3 years ago
13

Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4). What is the y-coordinate of the midpoint of line segment YZ?

Mathematics
1 answer:
tatiyna3 years ago
8 0

Given:

Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4).

To find:

The y-coordinate of the midpoint of line segment YZ.

Solution:

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

The endpoints of the line segment YZ are Y(-3,-6) and Z(7,4). So, the midpoint of YZ is:

Midpoint=\left(\dfrac{-3+7}{2},\dfrac{-6+4}{2}\right)

Midpoint=\left(\dfrac{4}{2},\dfrac{-2}{2}\right)

Midpoint=\left(2,-1\right)

Therefore, the y-coordinate of the midpoint of line segment YZ is -1.

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Type your answer and then click or tap Done.
masya89 [10]

Answer:

See below

Step-by-step explanation:

x(x-2y)-(y-x)2  

Final result :

-y2

Step by step solution :

Step  1  :

Equation at the end of step  1  :

x • (x - 2y) -  (y - x)2

Step  2  :

2.1     Evaluate :  (y-x)2   =    y2-2xy+x2  

Final result :

-y2

7 0
2 years ago
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mr Goodwill [35]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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Answer:

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Step-by-step explanation:

3 0
3 years ago
What are the possible values of x in x2 + 3x + 3 = 0?
stealth61 [152]
Hello,

x^2+3x+3=0\\&#10;&#10;\Delta=9-4*3=-3\\&#10;&#10;x= \dfrac{-3-i*\sqrt{3}}{2} \ or\ x= \dfrac{-3+i*\sqrt{3}}{2} \\&#10;&#10;
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the temper ire of chicken soup is 192.7 F as it cools the temperature of the soup decreases 2.3 what is the temperature of the s
ad-work [718]

The temperature of soup after 25 minutes is 135.2^{\circ}\ F

<em><u>Solution:</u></em>

The temperature of chicken soup is 192.7°F

As it cools, the temperature of the soup decreases 2.3°F per minute

Let the initial temperature be T_0

Let "t" be the time for rate of decrease

Set up an equation

Temperature = Initial temperature - decrease in temperature

Decrease in temperature = rate of decrease x time

Therefore,

T = T_0-2.3t

<em><u>To find the temperature of soup after 25 minutes, substitute t = 25</u></em>

T = 192.7 - 2.3 (25)\\\\T = 192.7 -57.5\\\\T = 135.2

Thus the temperature of soup after 25 minutes is 135.2^{\circ}\ F

5 0
3 years ago
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