Answer : The rate of depreciation is, $16000
Step-by-step explanation :
Formula used to calculate the rate of depreciation is:

Given:
Purchase price of asset = $15000
Salvage value = $7000
Estimate life asset = 3 years
Now put all the given values in the above formula, we get:

Deprecation rate = $16000
Therefore, the rate of depreciation is, $16000

We need to find the number of pies baked in years 1 and 2.
There were 148 pies baked in year 1. 
There were
pies baked in year 2. 
Rearrange the terms so the variable is first. 
Answer:
see explanation
Step-by-step explanation:
I don't have graphing facilities but can give you the vertex and 1 other point.
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = - 
y = - x² - 2x + 8 ← is in standard form
with a = - 1 and b = - 2 , then
x = -
= - 1
Substitute x = - 1 into the equation for corresponding value of y
y = - (- 1)² - 2(- 1) + 8 = - 1 + 2 + 8 = 9
vertex = (- 1, 9 )
To obtain another point substitute any value for x into the equation
x = 0 : y = 0 - 0 + 8 , then (0, 8 ) is a point on the graph
x = 2 : y = - (2)² - 2(2) + 8 = - 4 - 4 + 8 = 0 then (2, 0 ) is a point on the graph
Answer:
many things.
An algebraic expression is a variable expression is a combination of terms by the operations such as addition, subtraction, multiplication, division.
- here the algebraic expression is an addition