The distance from the center of dilation, P, to.the image vertice S' is; 6 units.
<h3>What is the distance from the center of dilation, P, to the image S'?</h3>
It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.
Hence, since the dilation factor as given in the task content is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6units.
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58% is the answer. 7 dividing 12= 0.5833333
you much move the decimal over two places and you would get 58%
I believe (3*8)*6=3*(8*6) illustrates the associative property of multiplication.
(3*8)*6=3*(8*6)
24*6=3*48
144=144
I don’t know sorry mansisnsiwhe sha
I did the problem myself and my teacher always said thatif you don't get the exact answer then round to the closest one. The answer that i got was 31,808.6, the closest one to that would be letter C.
