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daser333 [38]
3 years ago
10

Can you solve this problem

Mathematics
2 answers:
iren2701 [21]3 years ago
5 0

Answer:

6x^5 (^ is exponent)

Step-by-step explanation:

Because of simplification being the only thing we need to find, we can break things down.

3x^2 = 3 * x * x

2x^3 = 2 * x * x * x

Multiplying all of it is;

3 * 2 * x * x * x * x * x

Multiply number by number and variables by other variables to get:

6x^5

777dan777 [17]3 years ago
4 0
6x^5 ywwww this should be your answer
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10,14,16,18,20 plz I don't understand
joja [24]
10. b - 16.6 = -3.7.....add 16.6 to both sides
      b - 16.6 + 16.6 = -3.7 + 16.6
      b = -3.7 + 16.6
      b = 12.9

14. 18.91 = -7.9 + x.....add 7.9 to both sides
      18.91 + 7.9 = -7.9 + 7.9 + x
      26.81 = x

16. 295.8997 = -10.1k....divide both sides by -10.1
      295.8997 / -10.1 = (-10.1/-10.1)k
     - 29.297 = k

18. -94.4724 = 3.3x....divide both sides by 3.3
      - 94.4724 / 3.3 = (3.3 / 3.3)x
      - 28.628 = x

20. -29.4x = -148.764...divide both sides by -29.4
      (-29.4 / -29.4)x = - 148.764 / -29.4
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7 0
3 years ago
IM MARKING BRAINLIEST
nlexa [21]

5/6 yards

Step-by-step explanation:

\frac{1}{6}  +  \frac{4}{6}  =  \frac{5}{6}

8 0
3 years ago
Read 2 more answers
Find the perimeter of the figure to the nearest hundredth. 20mm 20mm 16mm. Please help me!
Sidana [21]

Answer:

The perimeter is 56mm

Step-by-step explanation:

N/B: the figure is not given, nevertheless we can infer that the figure is a triangular figure given that the lengths provided is just three.

So the perimeter is the distance around the object.

Perimeter =20+20+16= 56mm

6 0
3 years ago
Pls help me!! Show all work! I wil mark brainlest!!
vodka [1.7K]

Step-by-step explanation:

x = $5

y = $1

4x + 10y = $30

4(5) + 10(1) = 30

$20 + $10 = $30

5x + 5y = $30

5(5) + 5(1) = 30

$25 + $5 = $30

6 0
3 years ago
3^3 ÷ 9 / 11 - 2^2 <br> help me please?<br> it is a fraction
Travka [436]
<span>3^3 ÷ 9 / 11 - 2^2 
=27 </span>÷ 9 / 11 - 4
= 27 * 11/9 -4
= 297/9 - 4
=33-4
=29


4 0
3 years ago
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