The answer is c i’m pretty sure
Answer: yes.
Step-by-step explanation:
The scatter plot has been attached
Answer:
Options C, D & E are true
Step-by-step explanation:
Option A is wrong because from the scatter plot, only four athletes were faster in the second race than in the first one.
Option B is wrong because only 1 athlete had his second race time differing from the first race time by exactly 2 seconds.
Option C is true because exactly 9 of the times for the first race were at least 16 seconds
Option D is true because there are exactly 3 athletes who had the same time in both races
Option E is true because 8 of the times for the second race were less than 17 seconds
That is the answer , i looked it up for you my self :)
Answer:
side of 6.124 ft and height of 3.674 ft
Step-by-step explanation:
Let's s be the side of the square base and h be the height of the rectangular box.
The base and the roof would have an area of
and cost of
![4s^2 + 2s^2 = 6s^2](https://tex.z-dn.net/?f=4s%5E2%20%2B%202s%5E2%20%3D%206s%5E2)
The sides would have an area of 4sh and cost of 4sh*2.5 = 10sh
So the total cost for the material is
![6s^2 + 10sh = 450](https://tex.z-dn.net/?f=6s%5E2%20%2B%2010sh%20%3D%20450)
![10sh = 450 - 6s^2](https://tex.z-dn.net/?f=10sh%20%3D%20450%20-%206s%5E2)
![h = 45/s - 0.6s](https://tex.z-dn.net/?f=h%20%3D%2045%2Fs%20-%200.6s)
The volume of the shed has the following formula
![V = s^2h = s^2(45/s - 0.6s) = 45s - 0.6s^3](https://tex.z-dn.net/?f=V%20%3D%20s%5E2h%20%3D%20s%5E2%2845%2Fs%20-%200.6s%29%20%3D%2045s%20-%200.6s%5E3)
To find the maximum value for V, we can take its first derivative, and set it to 0
![\frac{dV}{ds} = 45 - 1.2s^2 = 0](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bds%7D%20%3D%2045%20-%201.2s%5E2%20%3D%200)
![1.2s^2 = 45](https://tex.z-dn.net/?f=1.2s%5E2%20%3D%2045)
![s^2 = 45 / 1.2 = 37.5](https://tex.z-dn.net/?f=s%5E2%20%3D%2045%20%2F%201.2%20%3D%2037.5)
![s = \sqrt{37.5} = 6.124 ft](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%7B37.5%7D%20%3D%206.124%20ft)
h = 45/s - 0.6s = 3.674 ft