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choli [55]
3 years ago
6

Can anyone plz help me with this?? Ans =22 But I don't know how?! ​

Mathematics
1 answer:
sukhopar [10]3 years ago
5 0

Answer:

first + all the digit then divide the rational than multiple it fro 5 then divide from 5 . the answer will appear

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How do i solve 3x+4-x=5x-16-7x?
rosijanka [135]

Answer:

x=-5

Step-by-step explanation:

Combine like terms:

2x+4=-2x-16

4x=-20

Solve

x=-5

8 0
3 years ago
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HELP ME PLSS !!!!!!!!!!!!!!!
FrozenT [24]

Answer:

x<8

Step-by-step explanation:

Had that same question

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2 years ago
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PLEASE I NEED THE ANSWER IN 5 MINUTES ITS FOR HOMEWORK AND THE TEACHER IS REALLY STIRCT !!!!!
Verizon [17]

Answer: yes, jake is incorrect. H-15

Step-by-step explanation:

H+10=25

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5 0
3 years ago
Segment AB has length a and is divided by points P and Q into AP , PQ , and QB , such that AP = 2PQ = 2QB. A) Find the distance
Deffense [45]

Answer:

A) \frac{7}{8}a

B) \frac{5}{8}a

Step-by-step explanation:

AB has length a and is divided by points P and Q into AP , PQ , and QB , such that AP = 2PQ = 2QB

A) Therefore, AP = 2QB

QB = AP/2

The midpoint of QB = QB/2 = (AP/2)/2 = AP/4

AP = 2PQ, Therefore PQ = AP/2

Since the length of AB = a

AB = AP + PQ + QB = a

AP + AP/2 + AP/2 = a

AP + AP = a

2AP = a

AP = a/2

The distance between point A and the midpoint of segment QB = AP + PQ + QB/2 = AP + AP/2 + AP/4 = 7/4(AP)

But AP = a/2

Therefore The distance between point A and the midpoint of segment QB =  7/4(a/2)= \frac{7}{8}a

B)

the distance between the midpoints of segments AP and QB = AP/2 + PQ + QB/2 = AP/2 + AP/2 + AP/4 = 5/4(AP)

But AP = a/2

Therefore the distance between the midpoints of segments AP and QB = 5/4(AP) = \frac{5}{4} *\frac{a}{2}=\frac{5}{8}a

7 0
3 years ago
Click once to choose an answer. Click again to change your answer. Choose all that locate the ordered pair in the correct quadra
forsale [732]

Answer:

Quadrant\ IV = (5, -3)

Quadrant\ I = (9, 11)

Quadrant\ II = (-1, 3)

Quadrant\ III = (-2, -4)

Step-by-step explanation:

Given

Quadrant\ IV = (5, -3)

Quadrant\ II  = (-4, -8)

Quadrant\ I = (9, 11)

Quadrant\ II = (-1, 3)

Quadrant\ III = (-2, -4)

Required

Determine which coordinate fall in the right quadrant

First, we split the each quadrant into x and y axis

In the first:

x and y is +

In the second:

x is - and y is +

In the third

x and y are -

In the fourth

x is + and y is -

Comparing the given coordinates to their respective quadrants, base on the conditions stated above

Quadrant\ IV = (5, -3)  is correct

Quadrant\ I = (9, 11) is correct

Quadrant\ II = (-1, 3) is correct

Quadrant\ III = (-2, -4) is correct

Quadrant\ II  = (-4, -8) is incorrect

3 0
3 years ago
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