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swat32
3 years ago
14

Basic Computation: Finding Probabilities, let z be a random variable with a standard normal distribution. Find the indicated pro

bability, and shade the corresponding area under the standard normal curve.
P(-1.20 = z = 2.64)
Mathematics
1 answer:
svp [43]3 years ago
7 0

Answer:

0.8808

Step-by-step explanation:

The objective is to calculate the probability of:

P(-1.20 ≤ z ≤ 2.64)

i.e. the probability that is the area between two z-values.

Thus;

P(-1.20 ≤ z ≤ 2.64) = P(z ≤ 2.64) - P( z ≤ 1.20)

From z table;

P(-1.20 ≤ z ≤ 2.64) = 0.9959 - 0.1151

P(-1.20 ≤ z ≤ 2.64) = 0.8808

We can see the shaded area under the standard normal curve from the image attached below.

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Y=-|x+3| domain and range
sergejj [24]

Answer:

the domain is that x is a set of real numbers.

the range is y ≤ -3

Step-by-step explanation:

y = -|x + 3|

y is either positive or equal to zero.

Now, x is all real numbers because any value of x used will yield a valid value of y.

Thus, we can say that the domain is that x is a set of real numbers.

Now, for the range:

The minus sign in front of the absolute value indicates that the function has a maximum value.

Thus, the range is y ≤ -3

5 0
3 years ago
If the smaller of two numbers is one half of the larger number and the sum of the two numbers is 60 find the numbers
Dennis_Churaev [7]

Larger number = X

Smaller number = 1/2X

X + 1/2X = 60

Simplify:

1 1/2x = 60

Divide both sides by  1 1/2:

x = 40

The numbers are 20 and 40

7 0
2 years ago
I need help please with this
yaroslaw [1]
The answer is 24
Explanation: no need for one :)
7 0
3 years ago
What will be the perimeter and the area of the rectangle below if it is enlarged using a scale factor of 3.5? (1 point)
Anna11 [10]

Answer:

2. Perimeter = 98 cm, área = 588 cm²

5 0
3 years ago
Four universities—1, 2, 3, and 4—are participating in a holiday basketball tournament. In the first round, 1 will play 2 and 3 w
notsponge [240]

Answer:

a) S= (1324

1342

1423

1432

2314

2341

2413

2431

3124

3142

3214

3241

4123

4132

4213

4231)

b) A= (1324

1342

1423

1432)

Step-by-step explanation:

The number of total outcome is given by,

T= 4×2×2×1=16

Listing them we have;

S=

(1324

1342

1423

1432

2314

2341

2413

2431

3124

3142

3214

3241

4123

4132

4213

4231)

b) A= (1324

1342

1423

1432)

7 0
3 years ago
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