Answer:
The amount of phosphorus-32 left after 100.1 days is <u>9.3 g</u>.
Step-by-step explanation:
Given:
Initial amount of Phosphorus-32 is, 
Time period of decay is, 
Half life of the block is, 
Now, final amount left is, 
We know that, the decay equation for a radioactive material is given as:

The value of the decay constant is given as:

Now, plug in all the given values and calculate 'N'. This gives,

Therefore, the amount of phosphorus-32 left after 100.1 days is 9.3 g