= 2025
When you are told to find the smallest length possible, you perform L.C.M(Least common multiples)
For this, you divide the given lengths using the numbers that divides all through.
I have added an image to this answer. Go through it for more explanation
The LCM will be the values that are common to both factors. From the given values the LCM will be 2² * 3² * 5
<h3>Least common multiple</h3>
LCM is the lowest number that can divide all other numbers given in an expression.
Given the prime factorizations 2² * 3² * 5 and 2*3*5. The LCM will be the values that are common to both factors.
From the given values the LCM will be 2² * 3² * 5
Learn more on LCM here: brainly.com/question/233244
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Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
S = 2 * (pi) * r * h.....for r
divide both sides by 2 * pi * h
s / (2(pi)h = r
Answer:
101.9 sq ft
Step-by-step explanation:
The figure is missing: find it in attachment.
Here we want to find the lateral surface area of the figure, which is the sum of the areas of all faces.
We have in total 5 faces:
- 1 of them is rectangle with sizes (8.5 ft x 3.3 ft), so its area is
- 1 of them is a rectangle with sizes (3.3 ft x 5.1 ft), so its area is
- 1 of them is a rectangle with sizes (6.8 ft x 3.3 ft), so its area is
- Finally, we have 2 triangular faces (top and bottom), so their area is
where
b = 5.1 ft is the base
h = 6.8 ft is the height (because the triangle is a right triangle)
So the area of the triangle is
So the total lateral surface area of the figure is:
