The unit rate will be 6 newspapers every 10 minutes.
Let
represent the depth of the miner and equipments elevator, respectively. We know that equipment elevator descends with a velocity of
feet per second, and the miners one descends with a velocity of
feet per second.
If we start counting time (
) when the equipment elevator begins to descend, after
seconds its depth will be

On the other hand, the miner elevator follows the same rule, but we have to use its velocity, and remember that it starts with a delay of thirty seconds:

Now, we have to wait the 30 seconds of delay, and then another 14 seconds. This means that we want to know the positions of both elevators when
. Let's plug this value into the two equations:


So, the equipment elevator is 176 feet deep, and the miner elevator is 210 feet deep, and thus this is the deeper one.
Answer:
13.9 or 14
Step-by-step explanation:
a^2 + b^2 = c^2
5^2 + 13^2 = c^2
25 + 169 = 197
square root 197 to get c
c = 13.9 (14 rounded up)
Helpful thing to note is that the hyptoenuse will always be longer than your "long side" of the triangle
Answer:
1. Sides 1 and 2 are congruent so sides 3 are also congruent
2. Since angles D and R are the same and the two sides are the same, the triangles are the same