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3 years ago

Area of circle 6mm(radius) in terms of pi

Mathematics

1 answer:

professor190 [17]3 years ago

5 0

Answer: 36π

Step-by-step explanation:

A = πr²

A = π(6)²

A = 36π

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Solve for c.<br><br> Solve for x.<br><br> Solve for c.<br><br> Solve for x.<br><br> Solve for x.

Mariana [72]

Answer:

1) The option $c=9-a+b$ is correct.

2) The option x=-2 or x=-3 is correct.

3) The option $c=9-a+b$ is correct.

4) The option $x=\frac{11}{3}$ is correct.

5) The option x=-2 or x=-3 is correct.

Step-by-step explanation:

1) Given equation is $\sqrt{a-b+c}=3$

Now to solve the equation for c:

$\sqrt{a-b+c}=3$

Squaring on both sides we get

$(\sqrt{a-b+c})^2=3^2$

$a-b+c=9$

$c=9-a+b$

Therefore the option $c=9-a+b$ is correct.

2) Given equation is $\sqrt{3x+10}=x+4$

Now to solve the equation for x:

$\sqrt{3x+10}=x+4$

Squaring on both sides we get

$(\sqrt{3x+10})^2=(x+4)^2$

$3x+10=x^2+8x+16$

$x^2+8x+16-3x-10=0$

$x^2+5x+6=0$ which is a quadratic equation in x.

We can solve it by finding factors

$x^2+5x+6=(x+2)(x+3)$

$(x+2)(x+3)=0$

x+2=0 or x+3=0

Therefore x=-2 or x=-3

Therefore the option x=-2 or x=-3 is correct.

3) Given equation is $\sqrt{a-b+c}=3$

Now to solve the equation for c:

$\sqrt{a-b+c}=3$

Squaring on both sides we get

$(\sqrt{a-b+c})^2=3^2$

$a-b+c=9$

$c=9-a+b$

Therefore the option $c=9-a+b$ is correct.

4) Given equation is $\sqrt{x+3}=2\sqrt{x-2}$

Now to solve the equation for x:

$\sqrt{x+3}=2\sqrt{x-2}$

Squaring on both sides we get

$(\sqrt{x+3})^2=(2\sqrt{x-2})^2$

$x+3=2^2(x-2)$

$x+3=4(x-2)$

$x+3=4x-8$

$4x-8-x-3=0$

$3x-11=0$

$x=\frac{11}{3}$

Therefore the option $x=\frac{11}{3}$ is correct.

5) Given equation is $\sqrt{3x+10}=x+4$

Now to solve the equation for x:

$\sqrt{3x+10}=x+4$

Squaring on both sides we get

$(\sqrt{3x+10})^2=(x+4)^2$

$3x+10=x^2+8x+16$

$x^2+8x+16-3x-10=0$

$x^2+5x+6=0$ which is a quadratic equation in x.

We can solve it by finding factors

$x^2+5x+6=(x+2)(x+3)$

$(x+2)(x+3)=0$

x+2=0 or x+3=0

Therefore x=-2 or x=-3

Therefore the option x=-2 or x=-3 is correct.

5 0

3 years ago

Read 2 more answers

Solve using<br> elimination <br> X- 2y = 3<br> 3x - y = 2

FrozenT [24]

<u>Answer:</u> x = 1/5 and y= -7/5

Step-by-step explanation: Let's solve your system by elimination.

Multiply the first equation by -3,and multiply the second equation by 1.

-3 (x - 2y = 3)

1 (3x - y = 2)

Becomes:

-3x + 6y = -9

3x -y = 2

Add these equations to eliminate x:

5y = -7

Then solve 5y = -7

5y/7 = -7/5

y = -7/5

Now that we‘ve found y, let’s plug it back in and solve for x.

Write down an original equation:

x - 2y = 3

<h3>Substitute -7/5 for y in x - 2y = 3:</h3><h3>x - 2 (-7/5) = 3</h3><h3>x + 14/5 = 3</h3><h3>x 14/5 + -14/5 = 3 + -14/5 (Add (-14)/5 to both sides)</h3><h3>x = 1/5</h3><h3><u>Answer: </u></h3><h3>x = 1/5 and y = -7/5</h3><h3 /><h3 /><h3 />

6 0

3 years ago

Is it right? or like idk i’m confused

Zina [86]

This is right

The system requires me to have 20 characters in my answer so I am just gonna add this.

6 0

3 years ago

Please answer this question

aliya0001 [1]

Answer:

y = 1 * 4^x

Step-by-step explanation:

the parental function of an exponential equation is y = ab^x

a is the initial y or the y intercept

b is the multiplier

so since the y intercept is a so far the equation is y = 1 * b^x

as stated above the multiplier is 4

that means the b is four

the equation is y = 1 * 4^x

7 0

2 years ago

8. Solve the equation below.

Fantom [35]

Answer:

x=5 and x=0

Step-by-step explanation:

4 0

3 years ago