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2 years ago

Which inequality has (–2.5, –4.5) as part of the solution set?

Mathematics

2 answers:

Katena32 [7]2 years ago

7 0

Answer:

it c

Step-by-step explanation:

Debora [2.8K]2 years ago

3 0

Answer:

the answer is c (x+2)^2/16 + (y+6)^2/16 <1

Step-by-step explanation:

on edge 2021 unit test got it right

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what is the common ratio for the geometric sequence below, written as a fraction? 768, 480, 300, 187.5, …

Crazy boy [7]

Let

$a1=768\\a2=480\\a3=300\\a4=187.5$

Step $1$

Find $\frac{a2}{a1}$

$\frac{a2}{a1} =\frac{480}{768}$

Divide by $96$ numerator and denominator

$\frac{480}{768} =\frac{\frac{480}{96}}{\frac{768}{96}} \\ \\ \frac{480}{768}=\frac{5}{8}$

$a2=a1*\frac{5}{8}$

Step $2$

Find $\frac{a3}{a2}$

$\frac{a3}{a2} =\frac{300}{480}$

Divide by $60$ numerator and denominator

$\frac{300}{480} =\frac{\frac{300}{60}}{\frac{480}{60}} \\ \\ \frac{300}{480}=\frac{5}{8}$

$a3=a2*\frac{5}{8}$

Step $3$

Find $\frac{a4}{a3}$

$a4=187.5 \\ a4=187\frac{1}{2} \\ \\ a4=\frac{375}{2}$

$\frac{a4}{a3} =\frac{\frac{375}{2}}{300} \\ \\ \frac{a4}{a3} =\frac{375}{600}$

Divide by $75$ numerator and denominator

$\frac{375}{600} =\frac{\frac{375}{75}}{\frac{600}{75}} \\ \\ \frac{375}{600}=\frac{5}{8}$

$a4=a3*\frac{5}{8}$

In this problem

The geometric sequence formula is equal to

$a(n+1)=a(n)*\frac{5}{8}\\$

For $n\geq 1$

therefore

the answer is

the common ratio for the geometric sequence above is $\frac{5}{8}$

6 0

3 years ago

Read 2 more answers

P(x)=-4x-2<br> Find p(a-3)

Marta_Voda [28]

Answer : -4a+10

Substitute (a-3) for x
-4(a-3)-2
-4a+12-2
-4a+10 but can also be written as -2(2a-5)

7 0

2 years ago

1 Given the functions f(x) and g(x) = find the following. 1 + x2 (a) (gºf)(x) 1 (b) (gºf)(6)

trapecia [35]

Okie so I can see you tomorrow and I’ll be right there on time to meet

8 0

3 years ago

A grocery store sells tangerines in 2/5 kg bags. A customer bought 4 kg of tangerines for a school party. How many bags did he b

Alex777 [14]

10kg bags I believe

8 0

2 years ago

Read 2 more answers

What is wrong with the following proof that for every integer n, there is an integer k such that n < k < n + 2? Suppose n

expeople1 [14]

Answer:

c)The proof writer mentally assumed the conclusion. He wrote "suppose n is an arbitrary integer", but was really thinking "suppose n is an arbitrary integer, and suppose that for this n, there exists an integer k that satisfies n < k < n+2." Under those assumptions, it follows indeed that k must be n + 1, which justifies the word "therefore": but of course assuming the conclusion destroyed the validity of the proof.

Step-by-step explanation:

when we claim something as a hypothesis we can only conclude with therefore at the end of the proof. so assuming the conclusion nulify the proof from the beginning

4 0

3 years ago