Hello from MrBillDoesMath!
Answer:
(3/4) a^(-5)b^(-3)c^2
Discussion:
(18 a^-3b^2c^6)/ (24 a^2b^5c^4) =
(18/24) a^ (-3-2) b^(2-5) c^(6-4) =
as a^-3/a^-2 = a ^ (-3-2) = a^(-5), for examples
(3/4) a^(-5)b^(-3)c^2
Thank you,
MrB
Step-by-step explanation:
and
are linear pair angles.

Hello :
the normal vector of the plane is : d' = [4,-1,5]...(vector perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .
I believe that the common difference would be.10