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Ahat [919]
2 years ago
11

Really need help emergency thanks if you help

Mathematics
2 answers:
OLEGan [10]2 years ago
8 0

Answer:D because you divide it bu a common factor

Step-by-step explanation:

andriy [413]2 years ago
6 0
It's D! 500/4 = 125
4/4 1
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Multiply (3x - 2)2.
alexandr1967 [171]
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How do I simplify this exponent problem???
Nikolay [14]

Hello from MrBillDoesMath!

Answer:

(3/4) a^(-5)b^(-3)c^2


Discussion:  

(18 a^-3b^2c^6)/ (24 a^2b^5c^4) =

(18/24) a^ (-3-2) b^(2-5) c^(6-4) =

                  as  a^-3/a^-2 = a ^ (-3-2) = a^(-5), for examples

(3/4) a^(-5)b^(-3)c^2


Thank you,

MrB

8 0
2 years ago
Please help ♡♡♡♡♡♡♡​
lions [1.4K]

Step-by-step explanation:

\angle AOB and \angle BOC are linear pair angles.

\therefore m\angle AOB + m\angle BOC = 180° \\  \therefore  \: 3x + 124 \degree + 6x + 29 \degree  = 180° \\  \therefore  \: 9x  + 153 \degree  = 180°  \\ \therefore  \: 9x  = 180°  - 153 \degree   \\ \therefore  \: 9x  = 27 \degree   \\ \therefore  \:x =  \frac{27 \degree }{9}  \\  \huge \pink{ \boxed{\therefore  \:x =3 \degree }} \\  \\  \because \: m\angle BOC =6x + 29 \degree   \\ \therefore \: m\angle BOC =6 \times3 \degree + 29 \degree   \\ \therefore \: m\angle BOC = 18\degree + 29 \degree    \\ \\   \huge \red{ \boxed{\therefore \: m\angle BOC = 47 \degree   }}

5 0
3 years ago
The line l passes through the point P = (1,-1,1) and has direction vector d = [2,3,1]. Determine whether l and the plane 4x-y+5z
suter [353]
Hello : 
the normal vector of the plane is : d' = [4,-1,5]...(vector  perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .
3 0
3 years ago
Instructions: Find the common difference of the arithmetic sequence.<br> 7.05, 7.15, 7.25,7.35, 7.45
zzz [600]
I believe that the common difference would be.10
7 0
3 years ago
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