First, we are given that the inscribed angle of arc CB which is angle D is equal to 65°. This is half of the measure of the arc which is equal to the measure of the central angle, ∠O.
m∠O = 2 (65°) = 130°
Also, the measure of the angles where the tangent lines and the radii meet are equal to 90°. The sum of the measures of the angle of a quadrilateral ACOB is equal to 360°.
m∠O + m∠C + m∠B + m∠A = 360°
Substituting the known values,
130° + 90° + 90° + m∠A = 360°
The value of m∠A is equal to 50°.
<em>Answer: 50°</em>
Answer:
8.4 cm^3 to the nearest tenth.
Step-by-step explanation:
The ratio of the volumes of the 2 cones is the ratio of the cubes of their radii.
So:
5^3 / 2^3 = 131 / v
v = 2^3 * 131 / 5^3
= 8 * 131 / 125
= 8.384.
On the negative plane field? because everything on the - side is negative.
