in the bag, there are certain number of toy- blocks with alphabets A,B,C and D written on them. The ratio of blocks A:B:C:D is 4 :7:3:1. if the number of A blocks is 50 more than the number of C blocks, what is the number of B blocks?
2 answers:
Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1 Let us consider the common ratio to be ‘x’. So, toy blocks with alphabet A is 4x and toy blocks with alphabet B is 7x and toy blocks with alphabet C is 3x and toy blocks with alphabet D is x Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks. As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively. So, 4x=50 + 3x x=50 Thus, the number of ‘B’ blocks is 7x = 7(50) = 350 350 is the required number.
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Answer:
350
Step-by-step explanation:
There are 4 ratio units of A blocks and 3 ratio units of C blocks, so 1 more ratio unit of A blocks than of C blocks. That 1 ratio unit corresponds to 50 blocks, since there are 50 more A blocks than C blocks.
There are 7 ratio units of B blocks, so the number of B blocks is ...
7×(50 blocks) = 350 blocks . . . . . number of B blocks
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Answer:
what you marked blue is right
Step-by-step explanation:
I think
A subtracted from b means b-a 7g+11 subtracted from 12 means 12-(7g+11)=12-1(7g+11)=12-7g-11=12-11-7g=1-7g