Answer:
(- 1, - 3 )
Step-by-step explanation:
Given the 2 equations
2x + y = - 5 → (1)
2x - 5y = 13 → (2)
Subtracting (1) from (2) term by term will eliminate the x-0 term
0 - 5y - y = 13 - (- 5) , that is
- 6y = 18 ( divide both sides by - 6 )
y = - 3
Substitute y = - 3 into either of the 2 equations and solve for x
Substituting into (1)
2x - 3 = - 5 ( add 3 to both sides )
2x = - 2 ( divide both sides by 2 )
x = - 1
solution is (- 1, - 3 )
Answer:
5k+9
Step-by-step explanation:
Since it's a square, all four sides are equal so divide the equation of the total by 4.
20k/4=5k
36/4=9
The length of one side of the garden can be represented by the expression:
5k+9
X = 26.89352
1. remove parenthesis
2. divide both sides by 14
Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0
The height should be around 9.19 or 9.2 if you round it up.
(if you need an explanation as to why i would be happy to help as well!)