Question

What is the solution of the system? Use the elimination method. {4x+2y=66x−4y=−12

Answer 1

Answer:

The Answer is B. The solution is (0,3).

Step-by-step explanation:

I took the quiz and this was the answer.

Answer 2

$\begin{bmatrix}4x+2y=6\\ 6x-4y=-12\end{bmatrix}$

$\mathrm{Multiply\:}4x+2y=6\mathrm{\:by\:}3: 12x+6y=18$
$\mathrm{Multiply\:}6x-4y=-12\mathrm{\:by\:}2: 12x-8y=-24$

$\begin{bmatrix}12x+6y=18\\ 12x-8y=-24\end{bmatrix}$

12x - 8y = -24
-
12x + 6y = 18
/
-14y = -42

$\begin{bmatrix}12x+6y=18\\ -14y=-42\end{bmatrix}$

$Solve\;-14y=-42 \;for\;y \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}-14 \ \textgreater \ \frac{-14y}{-14}=\frac{-42}{-14}$
y = 3

$\mathrm{For\:}12x+6y=18\mathrm{\:plug\:in\:} \:y=3$

$12x+6\cdot \:3=18 \ \textgreater \ \mathrm{Multiply\:the\:numbers:}\:6\cdot \:3=18 \ \textgreater \ 12x+18=18$

$\mathrm{Subtract\:}18\mathrm{\:from\:both\:sides} \ \textgreater \ 12x+18-18=18-18$

$\mathrm{Simplify} \ \textgreater \ 12x = 0 \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}12 \ \textgreater \ \frac{12x}{12}=\frac{0}{12} \ \textgreater \ x = 0$

$Therefore\;the\:solutions\:are\;y=3,\:x=0$

Hope this helps!