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horsena [70]
3 years ago
11

Which is bigger 500 ft or 40 ft?

Mathematics
2 answers:
Sav [38]3 years ago
8 0

Answer: 500 ft is bigger

Step-by-step explanation:

Helping Hand3 years ago
0 0

500ft
Because 40 is smaller than 500

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HELP ME GUYS
Tatiana [17]

Answer:

aida's work is the correct answer

7 0
2 years ago
A population of bacteria is introduced into a culture. the number of bacteria P can be modeled by P=500(1+4t/(50+t^2 )) where t
Dennis_Churaev [7]
P(t)=500(1+4t/(50+t^2 ))

P'(t) = 500 [(50+t^2).4 - 4t.2t]/(50+t^2)^2

  by the quotient rule

 500 (-4t^2 + 200)/(t^2 + 50)^2

Hence

 P'(2) = 500 . (-16 + 200)/54^2 ~= 31.6
6 0
4 years ago
B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =
jolli1 [7]

I suppose you mean

g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)

Differentiate one term at a time.

Rewrite the first term as

\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}

Then the product rule says

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'

Then with the power and chain rules,

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}

Simplify this a bit by factoring out \frac12 (36-x^2)^{-3/2} :

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}

For the second term, recall that

\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}

Then by the chain rule,

\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}

So we have

g'(x) = 18 (36-x^2)^{-3/2} + 18 (36-x^2)^{-1/2}

and we can simplify this by factoring out 18(36-x^2)^{-3/2} to end up with

g'(x) = 18(36-x^2)^{-3/2} \left(1 + (36-x^2)\right) = \boxed{18 (36 - x^2)^{-3/2} (37-x^2)}

5 0
3 years ago
A bakery has d dozen eggs in one refrigerator and 3 fewer dozen eggs in another refrigerator. Which expressions correctly show h
san4es73 [151]

Answer:  2 d - 3

Step-by-step explanation:

Here, the number of dozen eggs in one refrigerator = d

According to the question,

There are 3 fewer dozen eggs in another refrigerator.

⇒ The number of eggs in another refrigerator = d - 3

Thus, the total dozen of eggs in both refrigerator = the number of dozen eggs in first refrigerator + the number of dozen eggs in second refrigerator

= d + d - 3

= 2 d - 3

Which is the required expression.

3 0
3 years ago
Read 2 more answers
I forgot someone help me plz
o-na [289]
Write the conjugates of them then FOIL both the top and bottom, then factor

5 0
3 years ago
Read 2 more answers
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