Let a and b be store A and store B, respectively. Then:
3a+b=63
5a+4b=140
So
12a+4b=252
5a+4b=140
7a=112
a=16
b=15
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Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
Answer:
672 sq cm
Step-by-step explanation:
Each triangular base is 1/2 (12 * 8) or 48, making them = 96.
One of the sides is 12 x 18 = 216
The other 2 sides are 10 x 18 = 180 x 2 = 360
Add them all together to get 672 sq cm
Answer:
Step-by-step explanation:
Given that,
An airthmetic sequence,
261,256,251
We need to find the 50th term.
We have,
first term, a = 261
common difference = 256-261 = -5
The nth term of the AP is given by :
So, the 50th term of the sequence is 16.
A. 292.5
b. .65
c. 157.5
d. .35
