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3 years ago

Round 717.25 to the nearest tenth.

Mathematics

2 answers:

Vaselesa [24]3 years ago

7 0

Hi there!

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I believe your answer is:

717.3

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Here’s why:

The value of the hundredths place determines if we should round the tenths place up or down.

⸻⸻⸻⸻

$n \leq 4\text{ - Round Down}\\n \geq 5\text{ - Round Up}$

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Since the hundredths place is greater than or equal to 5, we will round up.

717.25

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 $717.25 \approx\boxed{717.3}$ 

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Hope this helps you. I apologize if it’s incorrect.

Mashutka [201]3 years ago

5 0

Answer:

717.3

Step-by-step explanation:

717.25

717.3

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Step-by-step explanation:

Here, we are interested in calculating the temperature at the end of the day.

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But throughout the day, the temperature increased by 16 degrees;

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Step-by-step explanation:

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Because of the relatively high interest rates, most consumers attempt to pay off their credit card bills promptly. However, this

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a. 0.4129 = 41.29% of the bank's Visa cardholders pay more than 29 dollars in interest.

b. 0.1867 = 18.67% of the bank's Visa cardholders pay more than 35 dollars in interest.

c. 0.0742 = 7.42% of the bank's Visa cardholders pay less than 14 dollars in interest.

d. An interest payment of $35.2 is exceeded by only 18% of the bank's Visa cardholders.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 27 dollars and a standard deviation of 9 dollars.

This means that $\mu = 27, \sigma = 9$

A. What proportion of the bank's Visa cardholders pay more than 29 dollars in interest?

This is 1 subtracted by the p-value of Z when X = 29, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{29 - 27}{9}$

$Z = 0.22$

$Z = 0.22$ has a p-value of 0.5871.

1 - 0.5871 = 0.4129

0.4129 = 41.29% of the bank's Visa cardholders pay more than 29 dollars in interest.

B. What proportion of the bank's Visa cardholders pay more than 35 dollars in interest?

This is 1 subtracted by the p-value of Z when X = 35, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{35 - 27}{9}$

$Z = 0.89$

$Z = 0.89$ has a p-value of 0.8133.

1 - 0.8133 = 0.1867

0.1867 = 18.67% of the bank's Visa cardholders pay more than 35 dollars in interest.

C. What proportion of the bank's Visa cardholders pay less than 14 dollars in interest?

This is the p-value of Z when X = 14. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{14 - 27}{9}$

$Z = -1.445$

$Z = -1.445$ has a p-value of 0.0742.

0.0742 = 7.42% of the bank's Visa cardholders pay less than 14 dollars in interest.

D. What interest payment is exceeded by only 18% of the bank's Visa cardholders?

This is the 100 - 18 = 82nd percentile, which is X when Z has a p-value of 0.82, so X when Z = 0.915.

$Z = \frac{X - \mu}{\sigma}$

$0.915 = \frac{X - 27}{9}$

$X - 27 = 0.915*9$

$X = 35.2$

An interest payment of $35.2 is exceeded by only 18% of the bank's Visa cardholders.

7 0

3 years ago