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castortr0y [4]
3 years ago
12

The area of a square boxing ring is 436 square feet. What is the approximate length, in feet, of one side of the boxing ring?

Mathematics
2 answers:
Irina-Kira [14]3 years ago
6 0
Squaring 436 gives you 20.8...therefore, approximately, one side is 21 ft
katrin [286]3 years ago
3 0
21ft because 436 squared is about 21.
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The equation of four lines are given below:
tia_tia [17]

Answer:

epic

Step-by-step explanation:

5 0
3 years ago
Write the subtraction expression as an equivalent addition expression and then evaluate it.
solniwko [45]

The subtraction expression is solved to get -27 gives while the equivalent addition expression is -65 + 35 evaluating gives -47

<h3>What is subtraction and addition?</h3>

Subtraction refers taking away a value from a certain value while addition implies increasing a value by a certain value

<u>Given data</u>

-15 - 12

solving we have

-15 - 12 = -27

equivalent addition

-62 + 35

evaluating the equivalent addition

-65 + 35 = --27

Read more on addition and subtraction here: brainly.com/question/4721701

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4 0
1 year ago
Mr.jone wants to buy 6 tickets to a play.Each ticket costs $10 Mr.Jone has $45 in his pocket. How much more money does he need t
Snowcat [4.5K]
He needs $15 more to buy the tickets.
8 0
3 years ago
Read 2 more answers
Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:
Nataly_w [17]
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)

</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so

</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>

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remember that 
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{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and 
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the answer is the option <span>B.)
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6 0
3 years ago
Read 2 more answers
SOMEONE PLEASE HELP ME ASAP PLEASE!!!!​
ehidna [41]

Answer:

Therefore,

a_{21}=2

Step-by-step explanation:

Given:

A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]

To Find:

a₂₁ = ?

Solution:

Let,

A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right]

We require  ' a₂₁ ' i.e Second Row First Column Element

So on Comparing we get

∴ a_{21}=2

Therefore,

a_{21}=2

5 0
3 years ago
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