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natta225 [31]
3 years ago
8

-7x + 2y = -5 y = -7x + 8 explain how please

Mathematics
1 answer:
Fiesta28 [93]3 years ago
7 0

Answer:

x = 1 and y =1

Step-by-step explanation:

y = -7x + 8

sub into other eq

-7x + 2(-7x + 8) = -5

-7x - 14x + 16 = -5

-21x = -21

x - 1

y = -7(1) + 8

y = 1

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Solve the system using the substitution method:<br> 3x + 5y = -10<br> X - 5y =-10
inn [45]

<u>Answer:</u>

Point Form:

(−5,1)

Equation Form:

x=−5, y=1

<u>Step-by-step explanation:</u>

Solve for the first variable in one of the equations, then substitute the result into the other equation.

1.  x=5y−10

2. 20y−30=−10

3. y=1

4. x=−5

4 0
3 years ago
Solve the whole problem i give brainliest please help me.
gladu [14]

Answer:

165 is greater than or equal to 17.75x+5.25; 9 is greater than or equal to x

Step-by-step explanation:

The problem states that they have no more than $165. This means that they either use all the money, or they have leftover money, which means you need to use the 'greater than or equal to' sign. It says that tickets are $17.75 a person, and we're trying to find the number of people (x). You can write this as 17.75x. There is also a parking fee to add on to the equation, which is represented as +5.25. Now, we can solve!

I'm going to use an equal sign to replace the inequality symbol, but make sure to add the symbol at the end of the problem.

165=17.75x+5.25

159.75=17.75x

9=x

Our final answer is 9 is greater than or equal to x. Hope this helps!

8 0
3 years ago
Read 2 more answers
PLEEZZ
jonny [76]

4 < 4(6y - 12) - 2y       |use distributive property

4 < (4)(6y) + (4)(-12) - 2y

4 < 24y - 48 - 2y       |add 48 to both sides

52 < 26y      |divide both sides by 26

2 < y → y > 2

---------------------------------------------------------

4x + 3 < 3x + 6      |subtract 3 from both sides

4x < 3x + 3       |subtract 3x from both sides

x < 3

------------------------------------------------------------

-5r + 6 ≤ -5(r + 2)        |use distributive property

-5r + 6 ≤ (-5)(r) + (-5)(2)

-5r + 6 ≤ -5r - 10         |add 5r to both sides

6 ≤ -10     FALSE

No solution

-------------------------------------------------------------

-2(6 + s) ≥ -15 - 2s        |use distributive property

(-2)(6) + (-2)(s) ≥ -15 - 2s

-12 - 2s ≥ -15 - 2s        |add 2s to both sides

-12 ≥ -15     TRUE

All real numbers

-------------------------------------------------------------

3s + 6 ≤ -5(s + 2)        |use distributive property

3s + 6 ≤ (-5)(s) + (-5)(2)

3s + 6 ≤ -5s - 10         |subtract 6 from both sides

3s ≤ -5s - 16        |add 5s to both sides

8s ≤ -16         |divide both sides by 8

s ≤ -2

--------------------------------------------------------------

4/3 s - 3 ?

4 0
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Answer:

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Step-by-step explanation:

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