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3 years ago

Find the volume of these composite figures.

Mathematics

1 answer:

trapecia [35]3 years ago

5 0

Answer:

60 all you have to do multiply them

Step-by-step explanation:

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I really need help with this right now :(

erma4kov [3.2K]

Lol sry nobody came to help you earlier...
honestly u shoould just put all the values in a calculator.
The second one, fourth one, and last one

4 0

3 years ago

1/6 + 1/8 + 1/12 what is the awnser

HACTEHA [7]

Answer:

3/8 (Decimal: 0.375)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Jacob made a banner for a sporting event in the shape of a parallelogram the area of the banner is 127 1/2 square centimeters th

Firlakuza [10]

For a parallelogram, the area is calculated by the equation,
A = bh
where A is area, b is base, and h is height. From this equation, we can solve for the base of the banner by dividing the area by the height.
base of the banner = 127.5 cm² / 4.25 cm
base of the banner = 30 cm
Thus, the measure of the base of the banner is equal to 30 cm.

8 0

3 years ago

Please help me

lesya [120]

1_ 0/4. ( if toss a coin twice, we won't have three results)

2_ 0/4

3_ 3/4

4_ 3/4

5 _ 1/4

6_ 1/4

good luck

4 0

3 years ago

2. Solve the system of equations. Write your answer in parametric vector notation. X, +5x2 + 4x3 + 3x4 +9xs = 18 2x, +6x2 + 4x3

ratelena [41]

Answer:

The system is inconsistent.

Step-by-step explanation:

The system is

$x_1+5x_2+4x_3+3x_4+9x_5=18\\2x_1+6x_2+4x_3+6x_4+6x_5=28\\3x_1+7x_2+4x_3+10x_4+x_5=41\\4x_1+6x_2+2x_3+7x_4+4x_5=29$

The associated matrix to the system is

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\2&6&4&6&6&28\\3&7&4&10&1&41\\4&6&2&7&4&29\end{array}\right]$

Now we use row operations to find the echelon form of the matrix:

1. We substract to row 2, two times the row 1.

We substract to row 3, three times the row 1.

We substract to row 4, four times the row 1 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&-4&-4&0&-12&-8\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]$

2. We multiply the second row of the preview step by -1/4. We obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]$

We add to row 3, eight times the row 2.

We add to row 4, fourtheen times the row 2 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&-5&10&-155\end{array}\right]$

4. We add to row 4 of the preview step, five times the row 3 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&0&0&-140\end{array}\right]$

Using backward substitution we have that

$0x_5=-140$ , then $0=-140$ and this is absurd. Then The system is inconsistent.

4 0

3 years ago