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LuckyWell [14K]
2 years ago
14

Evaluate f(2) - f(-1) when f(x) = 6x² - 1

Mathematics
1 answer:
Illusion [34]2 years ago
7 0

Answer:

f(x) = 6 x^2 - 1

f(2) = 6 * 2^2 - 1 = 23

f(-1) = 6 * -1^2 - 1 = 6 * 1 - 1 = 5

f(2) - f(-1) = 23 - 5 = 18

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What is the equation of the line in slope-intercept form with slope -3/2 and y-intercept -5?
V125BC [204]

About Slope Intercept Form:

  • y = mx + b
  • m represents the slope
  • b represents the y-intercept or AKA the starting point

ABOUT PROBLEM:

  • Since -3/2 is the slope, it represents m in Slope Intercept Form
  • Since -5 is the y-intercept, it represents b in Slope Intrecept Form

y = mx + b

y = -3/2x + -5 --- IN Slope Intercept Form


Hope this helps you!!! :)


5 0
3 years ago
Given the function g(x) = 4(3)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
LenaWriter [7]
Easy peasy


the average rate of change in section A is the slope from (1,g(1)) to (2,g(2))
the average rate of chagne in section B is the slope from (3,g(3)) to (4,g(4))



A.

section A
g(1)=4(3)^1=12
g(2)=4(3)^2=4(9)=36
slope=(36-12)/(2-1)=24/1=24

section B
g(3)=4(3)^3=4(27)=108
g(4)=4(3)^4=4(81)=324
slope=(324-108)/(4-3)=216/1=216



section A has an average rate of change of 24
section B has an average rate of change of 216
3 0
3 years ago
One fourth of the 120 students took wood shop. How many students did not take wood shop?
yawa3891 [41]

Answer:

90 students.

Step-by-step explanation:

Given 1/4 of the 120 students took woodshop, just take the 3/4 that didn't take it:

\frac{3}{4}(120)

Find common factors between 4 and 120 to simplify, so 4.

\frac{3}{1} (30)

Now multiple across to get 90.

5 0
3 years ago
The chickens on a certain farm consumed 600 pounds of feed in half a year. During that time the total number of eggs laid was 5,
raketka [301]
600*1,25$=750$
\frac{750}{5000}=\frac{3}{20}=0,15
8 0
3 years ago
Read 2 more answers
The graph of a system of equations will intersect at more than one point?
Bess [88]
I believe the answer is sometimes
6 0
3 years ago
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