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PSYCHO15rus [73]
3 years ago
14

There are 2.54 centimeters in 1 inch. There are 100 centimeters in 1 meter. To the nearest meter, how many meters are in 437 in

ches
Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0

Answer:

11.0998 = 11 meters

Step-by-step explanation:

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Answer:

To be honest i dont even know

Step-by-step explanation:

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3 years ago
What is the surface area of 5, 8, and 3
Rashid [163]

Answer:

158

Step-by-step explanation:

5*8=40

8*3=24

3*5=15

Each of these measurements gets added twice, becasue there are 6 faces on a rectangular prism.

40 + 40 + 24 + 24 + 15 + 15 = 158

5 0
3 years ago
Read 2 more answers
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
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3 years ago
The first four terms of a sequence are shown below. 6, 2, -2, -6 Which of the following functions best defines this sequence?
klasskru [66]
Where are the functions?
your question is incomplete?
3 0
3 years ago
For nitrogen to be a liquid, its temperature must be within 12.78 °F of –333.22 °F. Which equation can be used to find the maxim
ziro4ka [17]
To determine the maximum and minimum temperatures at which nitrogen remains a liquid, use the equation |x - (-333.32)| = 12.78, where x is equal to the maximum and minimum temperatures. Using this equation, the maximum temperature is -320.54 degrees Fahrenheit while the minimum is -346.10 degrees Fahrenheit.
3 0
3 years ago
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