The area of the shaded region = 330 sq cm
Step-by-step explanation:
Given,
The radius of small circle (r) = 4 cm
The radius of large circle (R) = 11 cm
To find the shaded region
Formula
The area of circle of radius r = π
sq cm
So, The radius of the small circle = π×
sq cm = 16π sq cm
The radius of the large circle = π×
sq cm = 121π sq cm
Hence the area of the shaded region = 121π-16π sq cm
= 105π sq cm
= 105 ×
sq cm = 330 sq cm
Answer:
the positive slope of the asymptote = 5
Step-by-step explanation:
Given that:

Using the standard form of the equation:

where:
(h,k) are the center of the hyperbola.
and the y term is in front of the x term indicating that the hyperbola opens up and down.
a = distance that indicates how far above and below of the center the vertices of the hyperbola are.
For the above standard equation; the equation for the asymptote is:

where;
is the slope
From above;
(h,k) = 11, 100
= 100
a = 
a = 10

b = 
b = 2


y = 5x-53 , -5x -57
Since we are to find the positive slope of the asymptote: we have
to be the slope in the equation 
= 
= 5
Thus, the positive slope of the asymptote = 5
First we define variables:
x: Money Peter receives
y: Money Paul receives
z: Money Jane receives
We write the system of equations:
x / y = 13/12
x / z = 13/7
x = z + 78
Solving the system we have:
x = $ 169
y = 156 $
z = 91 $
Answer:
Paul gets 156 $
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