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2 years ago

What is the simplest form of this expression? 2(y-1) 8

Mathematics

1 answer:

NemiM [27]2 years ago

7 0

I hope this works

2(y-1)8=

16(y-1)

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Solve for r: 8x+36 5x + 60°

Ksju [112]

Answer:

Step-by-step explanation:763

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2 years ago

What is the difference between discrete vs continuous data

Sergeeva-Olga [200]

With continuous data, it is possible to find the midpoint of any two distinct values. For instance, if h = height of tree, then its possible to find the middle height of h = 10 and h = 7 (which in this case is h = 8.5)

On the other hand, discrete data can't be treated the same way (eg: if n = number of people, then there is no midpoint between n = 3 and n = 4).

-------------------------------------

With that in mind, we have the following answers

1) Continuous data. Time values are always continuous. Any two distinct time values can be averaged to find the midpoint

2) Continuous data. Like time values, temperatures can be averaged as well.

3) Discrete data. Place locations in a race or competition are finite and we can't have midpoints. We can't have a midpoint between 9th and 10th place for instance.

4) Continuous data. We can find the midpoint and it makes sense to do so when it comes to speeds.

5) Discrete data. This is a finite number and countable. We cannot have 20.5 freshman for instance.

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3 years ago

Please help me! I will mark you as the best answer

zmey [24]

Answer:

75/4 = 18.75

Step-by-step explanation:

Because a squar is 4 sides add 75 is the perimiter

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3 years ago

Jim earns $1,600 per month after taxes. He is working on his budget and has the first three categories finished. Why will he hav

marissa [1.9K]

What are the answers?

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3 years ago

Looking for the answer to this

SashulF [63]

<h2>Required Answer :-</h2>

Given system of linear equations are ,

x + y = 2
-3x + y = 2

And we need to find the Solution of the linear equation . So let's Firstly number the equations .

$\large{\red{\frak{ Given}}}\begin{cases} \sf x + y = 2\qquad ..........(i) \\\\\sf -3x + y = 2 \qquad ..........(ii) \\\end{cases}$

→ Multiplying equⁿ (i) by 3 ,

=> 3 ( x + y ) = 2*3

=> 3x + 3y = 6

→ Adding the two equations ,

=> 3x + 3y -3y + y = 6 + 2

=> 4y = 8

=> y = 8/4

=> y = 2

→ Put y = 2 in (i) ,

=> x + y = 2

=> x + 2 = 2

=> x = 2- 2

=> x = 0

<h3>★ Hence the required solution is ( 0 , 2 ) .</h3>

7 0

3 years ago