<span>The correct answer to this question is 3.0
Explanation:
Since the displacement is defined to be the change in position of an object.
Displacement is a vector. This means it has a direction as well as a magnitude and is represented visually as an arrow that points from the initial position to the final position.
Displacement = âš3^2+(4-4)^2) = 3</span>
graph (-3, 5)
because you would set it equal to 0 so it would be x + 3 = 0 then subtract 3 on both sides to get x = -3
same thing with x-5
set it equal to 0 to get y - 5 = 0 then just add 5 to get y=5
12 boys and 27 girls
1) Add 4 to 9. 13
2) 39 divided by 13 is 3
3)Multiple 3 to 4 boys and 9 girls. 3x4 is 12 boys, 3x9 is 27 girls
Hope this helps!
Answer:
The area of the given polygon is:
Step-by-step explanation:
To find the area of the polygon in the picture, you can divide the polygon in three rectangles: a 3 cm by 14 cm, a 5 cm by 14 cm rectangle, and the last rectangle must have a base of 12 cm (20 cm - 3 cm - 5 cm), and a height of 10 cm (14 cm - 4 cm). We can calculate the area of the rectangles with the formula below:
- Area of a rectangle = Base * height
Now, we're gonna replace the measurements in the formula.
<em>First rectangle:</em>
- Area of a rectangle = 3 cm * 14 cm
- <u>Area of a rectangle = 42 cm^2</u>
<em>Second rectangle:</em>
- Area of a rectangle = 5 cm * 14 cm
- <u>Area of a rectangle = 70 cm^2</u>
<em>Third rectangle:</em>
- Area of a rectangle = 12 cm * 10 cm
- <u>Area of a rectangle = 120 cm^2</u>
By last, we must add the area of the rectangles:
- Area of the polygon = 42 cm^2 + 70 cm^2 + 120 cm^2
- <u>Area of the polygon = 232 cm^2</u>
As you can see, <em><u>the area of the polygon in the picture is 232 cm^2</u></em>.
Do you know the Rational Roots Theorem? You could dream up possible rational roots by writing them in the form
plus or minus {1,2, 3,6} OVER plus or minus {1,2,5,10}. For example, 3/10 is rational and just might be a rational root. Next, determine whether or not this is a rational root here thru synthetic division.
If you do not know this theorem, consider using one of the following:
quadratic formula
completing the square
graphing (look for the x-values at which the parabolic graph here crosses the x-axis).
