Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
Answer:
Step-by-step explanation:
1 ) Y∝ 1 / X
Y = k / X
Y = 9 , X = -5
Putting the values in the relation above
9 = k / - 5
k = -45
Y = - 45 / X
Put Y = - 6
- 6 = - 45 / X
X = - 45 / -6
= 7.5
2 )
Luke and Nora can peel 12 carrots in 5 minutes
in 1 minute Luke and Nora can peel 12 / 5 carrot
in 1 minute Luke alone can peel 12/ 11 carrot .
In 1 minute Nora alone will peel (12 / 5 - 12/ 11 ) carrot
(12 / 5 - 12 / 11 )
= 2.4 - 1.1
= 1.3 carrot
In 1 minute Nora alone will peel 1.3 carrot
1.3 carrot in 1 minute
8 carrot in 8 / 1.3 minute
= 6.15 minutes.
In 1 minute Nora alone will peel 8 carrot in 6.15 minutes working alone.
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
Answer:
78
Correct term:60
Step-by-step explanation:
We are given that
The quotient of this expression is given by
We have to find the term in this expression which contains an error.
The quotient of this expression is given by
Using the formula
We can see that in the given expression there is 60 in place of 78.
The error in the expression of quotient is 78.
Correct term is 60.
Run and nug is the answer