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3 years ago

What is the inverse of f(x)=6x^2

Mathematics

1 answer:

likoan [24]3 years ago

8 0

Answer:

f^-1 (x) = √ 6x/6 - √ 6x/6

Step-by-step explanation:

interchange the variables and solve for y.

sorry its a little hard to read i didnt have all the symbols on my keyboard

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Consider this expression.

schepotkina [342]

Answer:

$9m^2 + 17m- 9$

Step-by-step explanation:

Given

$7m^2 + (2m - 1)(m + 9)$

Required:

Simplify

We start by opening the bracket

$7m^2 + (2m(m + 9) - 1(m + 9))$

$7m^2 + 2m^2 + 18m - m - 9$

Collect Like Terms

$9m^2 + 17m- 9$

Hence, the equivalent expression is $9m^2 + 17m- 9$

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2 years ago

Please help will mark brainliest since nobody answers my questions anymore lol

vovikov84 [41]

Answer: I think its the last one

Step-by-step explanation:

i might be wrong so its ok not o mark me the brainliest

6 0

3 years ago

Read 2 more answers

Please help!! and please show the work and the answer!!

kumpel [21]

Company 1: (24 + 26 + 28 + 23 + 21) / 5 (this is how many numbers added together) = 24.4

Company 2: (6 + 32 + 9 + 31 + 21) / 5 = 19.8

Company 3 (15 + 15 + 15 + 15 + 15) / 5 = 15

Company 4: (13 + 10 + 45 + 12 + 15) / 5 = 19

Company 1 has the longest average commute time per employee.

5 0

3 years ago

What is the point slope form of the line with slope −14 that passes through the point (−2, 9)?

RoseWind [281]

Answer:

the point slope is: y-9= -14(x+2)

7 0

3 years ago

Evaluate exactly without the use of a calculator (remember to rationalize any denominators). a.(cos 60o)(sin 270o) + tan 225o b.

Rom4ik [11]

Given:

The trigonometric expressions are given as,

$\begin{gathered} a)\text{ }(\cos 60\degree)(\sin 270\degree)+\tan 225\degree \\ b)-\tan 240\degree+(cos45\degree)(\sec 135\degree) \end{gathered}$

Explanation:

The given expression can be rewritten as,

$=(\cos 60\degree)(\sin (360\degree-90\degree))+\tan (270\degree-45\degree)\text{ . . . . .(1)}$

Since, from the trigonometric ratios,

$\begin{gathered} \sin (360\degree-90\degree)=-\sin 90\degree \\ \tan (270\degree-45\degree)=\cot 45\degree \end{gathered}$

On plugging the obtained ratios in equation (1),

$=(\cos 60\degree)(-\sin 90\degree)+\cot 45$

Substitute the trigonometric values in the above equation.

$\begin{gathered} =\frac{1}{2}(-1)+1 \\ =-\frac{1}{2}+1 \\ =\frac{1}{2} \end{gathered}$

Hence, the exact value of the expression is 1/2.

The given expression can be rewritten as,

$=-\tan (270\degree-30\degree)+(\cos 45\degree)(\sec (90\degree+45\degree))\text{ . . . ..(2)}$

Since, from the trigonometric ratios,

$\begin{gathered} \tan (270\degree-30\degree)=\cot 30\degree \\ \sec (90\degree+45\degree)=-\csc 45\degree \end{gathered}$

On plugging the obtained ratios in equation (2),

$=-\cot 30\degree+(\cos 45\degree)(-\csc 45)$

Substitute the trigonometric values in the above equation.

$\begin{gathered} =-\sqrt[]{3}+\frac{1}{\sqrt[]{2}}(-\sqrt[]{2}) \\ =-\sqrt[]{3}-1 \end{gathered}$

Hence, the exact value of the expression is -√3-1.

7 0

1 year ago