The length of the route of a bicylist that has covered 5/7 of his route and an additional 40 miles and yet to cover 118 miles less than 0.75 of his route is 168 miles.
<h3>How to form equation and solve for the variable?</h3>
The bicyclist covered 5 / 7 of his route and an addditional 40 miles.
Let
x = distance of his route in miles
Hence,
distance covered = 5 / 7 x + 40
He has yet to cover 118 miles less than 0.75 of his route. Therefore,
distance not covered = 0.75x - 118
Distance of his route = 5 / 7 x + 40 + 0.75x - 118
x = 5 / 7 x + 40 + 0.75x - 118
x = 1.464x - 78
x - 1.464x = -78
-0.464x = -78
x = 78 / 0.464
x = 168.103448276
x = 168 miles
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Answer:
it may be A log x ........
Answer:
a. 21 327 hot dogs/run
b. 70 runs/yr
c. 4 da/run
Step-by-step explanation:
Data:
Production rate (p) = 5000/da
Usage rate (u) = 260/da
Setup cost (S) = $66
Annual carrying cost (H) = $0.45/hot dog
Production days (d) = 294 da
Calculations:
a. Optimal run size
(i) Annual demand (D) = pd = (5000 hot dogs/1 day) × (294 days/1 yr)
= 1 470 000 hot dogs/yr
(ii) Economic run size



= 21 327 hot dogs/run
b. Number of runs per year
Runs = D/Q₀ = (1 470 000 hot dogs/1yr) × (1 run/21 327 hotdogs)
= 70 runs/yr
c. Length of a run
Length = Q₀/p = (21 327 hot dogs/1 run) × (1 da/5000 hot dogs)
= 4 da/run
Y - y₁ = m(x - x₁)
y - 5 = ⁵/₆[x - (-6)]
y - 5 = ⁵/₆(x + 6)
y - 5 = ⁵/₆(x) + ⁵/₆(6)
y - 5 = ⁵/₆x + 5
+ 5 + 5
y = ⁵/₆x + 10
y - y₁ = m(x - x₁)
y - 5 = -1¹/₅[x - (-6)]
y - 5 = 1¹/₅(x + 6)
y - 5 = 1¹/₅(x) + 1¹/₅(6)
y - 5 = 1¹/₅x + 7¹/₅
+ 5 + 5
y = 1¹/₅x + 12¹/₅