Why is the vertex of vertex form y=a(x-h)^2+k (h,k) rather than (-h,k)? If that was y=2(x-5)^2+6, the vertex would be at (5,6) w
1 answer:
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Answer:
(5, 6) is (h, k)
Step-by-step explanation:
Vertex form is an instance of the transformation of parent function f(x) = x². It is vertically scaled by a factor of 'a', and translated so the vertex is point (h, k). That is, the transformed vertex is h units right and k units up from that of the parent function (0, 0).
Parent:
f(x) = x^2
Transformed:
f(x) = a(x -h)^2 +k
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When you compare the form to your specific instance, you need to pay attention to what it is that you're comparing. As the attachment shows, ...
- a = 2
- -h = -5 ⇒ h = 5
- k = 6
Hence the vertex is (h, k) = (5, 6). The second attachment shows this on a graph.
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Answer:
Quotient is and remainder is 0.
Step-by-step explanation:
Given:
Dividend =
Divisor =
The long division is shown in the attachment.
Step 1: we need to divide with
we first multiply
with 3x we get the remainder as
Quotient as 3x.
Step 2: Now the dividend is and divisor
now we will multiply
with -5 we get the remainder as 0 and Quotient as
Hence Quotient is and remainder is 0.
