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Nat2105 [25]
3 years ago
14

15 + 1/4p = 2 A.60 B.-52 C.52 D.-60

Mathematics
1 answer:
gladu [14]3 years ago
6 0

Answer:

c

Step-by-step explanation:

subtract 15 and then multiply by 4. because you need to multiply by the reciprocal

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The area of a square garage is 144 square feet. What is the perimeter of the garage?
devlian [24]

Answer: The perimeter of the garage is 48

Area of a square = 144

a x a = 144

a = 12

Perimeter = 4a

= 4 x 12

= 48

7 0
2 years ago
Use the number line below, where RS = 7y +3, ST = 5y +8, and RT = 83.
Llana [10]

Answer:

Step-by-step explanation:

Given the vectors based on the number line as RS = 7y +3, ST = 5y +8, and RT = 83, the equation RS+ST = RT will be used to get the unknown.

Substituting the given equation into the expression we will have;

7y +3+5y +8 = 83

collect like terms'

7y+5y+3+8 = 83

12y + 11 = 83

12y = 83-11

12y = 72

y = 72/12

y = 6

b) Substitute y = 6 into RS and ST

Given RS = 7y+3

RS = 7(6)+3

RS = 42+3

RS = 45

For ST;

ST = 5y+8

ST = 5(6)+8

ST = 30+8

ST = 38

6 0
4 years ago
Please hurry. Solve the equation
Lelu [443]

The value of x is 5\sqrt[3]{25}.

Solution:

Given expression is -7=8-3 \sqrt[5]{x^{3}}.

Switch both sides.

8-3 \sqrt[5]{x^{3}}=-7

Subtract 8 from both side of the equation.

8-3 \sqrt[5]{x^{3}}-8=-7-8

-3 \sqrt[5]{x^{3}}=-15

Divide by –3 on both side of the equation.

$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}

\sqrt[5]{x^{3}}=-5

To cancel the cube root, raise the power 5 on both sides.

(\sqrt[5]{x^{3}})^5=(-5)^5

x^3=3125

To find the value of x, take square root on both sides.

\sqrt[3]{x^3}=\sqrt[3]{25}

x=5\sqrt[3]{25}

Hence the value of x is 5\sqrt[3]{25}.

5 0
3 years ago
PLEASE HELPPPPP Write an expression that converts the indicated units:
jasenka [17]

Answer:

1ft=12in

1in=1/12

1000m=1km

1d=86400s

3 0
3 years ago
Juan counts up by 3's and Alex counts up by 5's.What is the smallest number that they both say?
marshall27 [118]
15 the answer would be and is 15
5 0
3 years ago
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