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nalin [4]
4 years ago
10

1. Dorian has two bags. Each bag has the letters A, B, and C written on little pieces of paper inside of it. He draws one letter

from each bag.
What is the probability that he draws out a vowel and a consonant?
Mathematics
2 answers:
Serga [27]4 years ago
6 0
The probability of drawing a vowel and a constant in any order...

for consonant first..

(2/3)(1/3)=2/9

for vowel first 

(1/3)(2/3)=2/9

So the probability of getting a vowel and consonant in either order is:

2(2/9)=4/9
NNADVOKAT [17]4 years ago
4 0

Answer:

I fact checked the other guy, he is right.

Step-by-step explanation:


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Can someone please help with this or explain how to do it. I'm not very sure where to begin ToT
larisa86 [58]

Answer:

d. 12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

Step-by-step explanation:

First, we find the greatest common factor of 12x^23y^40z^9 and 10x^78z^5.

We work on the numbers, then on x, then on y, then on z.

We start with the GCF of 12 and 10.

10 = 2 * 5

12 = 2 * 3 * 3

The only factor 10 and 12 have in common is 2, so the GCF of 12 and 10 is 2.

Now we work on x. We have x^23 and x^78.

x^23 has 23 factors of x.

x^78 has 78 factors of x.

Since x^23 and x^78 have both at least 23 factors of x, x^23 is the GCF of x.

Now we work on y.

There is y^40 in one term, but there is no y in the other term. There is no GCF for the y.

Now we work on z. The first term has z^9. the second term has z^5. They both have at least 5 factors of z, so the GCF of z is z^5.

Now we put all the parts of the GCF together, and the GCF of the two terms is

2x^23z^5

We use option d. to factor.

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(___a____ + ____b___)

We already have the GCF outside the parentheses. Now we need to figure out what goes inside the parentheses.

The terms that go in positions a and b are the terms that when multiplied by the GCF give you the original expression.

We now work on position a.

What do you multiply by 2x^23z^5 to get 12x^23y^40z^9?

Answer: 6y^40z^4

Now we have

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + ____b___)

Now we do the same for position b.

What do you multiply by 2x^23z^5 to get 10x^78z^5?

Answer: 5x^55

Now we have

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

Answer: d. 12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

5 0
3 years ago
Please help i wil give brainlesit
irakobra [83]
I got 14 because since it’s a 90 degree angle I subtract 90 by 62 to get 28 and since x is multiplying by 2 it would have to be 14
5 0
3 years ago
Read 2 more answers
A coca cola costs 150 yen. You buyed 30 bottles of cola and sold them at the price of 155 yen each. Find profit %​
bazaltina [42]
<h3><u>Question:</u><u>-</u></h3>

A coca cola costs 150 yen. You buyed 30 bottles of cola and sold them at the price of 155 yen each. Find profit %

<h3><u>Answer</u><u>:</u><u>-</u></h3>

3.33%

<h3><u>Explanation</u><u>:</u><u>-</u></h3>

Cost price = ¥150

Selling price = ¥155

Total profit = Selling price - Cost price

→ = ¥155 - ¥150

→ = ¥5

Profit % = Profit × 100/cost price

️ = 5 × 100/150

️ = 10/3 = 3.33%

7 0
3 years ago
Lines AC and ED intersect at point B. If the m∠ABD = 5x - 5 and the m∠EBC = 3x + 15, ∠ABD and ∠EBC are what kind of angles?
Paraphin [41]

If Lines AC and ED intersect at point B, then ∠ABD and ∠EBC are vertically opposite angles

The point where two lines meet is known as an angle.

If line Lines AC and ED intersect at point B, then ∠ABD and ∠EBC will be vertically opposite to each other (They will be equal).

To show that the are equal

Given the angles

m∠ABD = 5x - 5

m∠EBC = 3x + 15

m∠ABD = m∠EBC (vertical angles)

5x - 5 = 3x + 15

5x - 3x = 15 + 5

2x = 20

x = 10

Substitute x = 10 into m∠ABD and m∠EBC

m∠ABD = 5x - 5

m∠ABD = 5(10)-5

m∠ABD = 50 - 5

m∠ABD = 45

Get m∠EBC

m∠EBC = 3x+15

m∠EBC = 3(10)+15

m∠EBC  = 30+15

m∠EBC  = 45 degrees

We can see that both angles are equal. Hence we can also conclude that they are vertically opposite angles

Learn more here: brainly.com/question/23466343

3 0
3 years ago
Plz help me with these I wanna be done with my homework lol
yaroslaw [1]
3. $69.60
5.51 problems
6 0
3 years ago
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