Answer:
The structural adaptations of the flying squirrel has developed a good sense of balance, sail-like fur skin membrane that extends from the wrists to ankles, delicate wrist bones that control this membrane, allowing the squirrel to steer, and a fluffy tail that balances out and stabilizes the flight.
<span>The type of isolation that describes the
statement above where in the species are being spread out and far over the area
is broad geographic range, for the broad geographic range is having species in
a state that they are being isolated in a way of having them spread out in a
particular area but too far from each other, where it describes and are related
to the statement being said above.</span>
Answer:
The answer is B. from east to west
<span>Type B = 11.52%
Type AB = 3.84%
Since blood type is determined by the presence or absence of the A and B genes and neither gene is dominant, we have a 3x3 grid where the rows and columns are both labeled A,B,O and the resulting 9 intersections are labeled A, B, AB, and O. Since the only homozygous entry we have numbers for is the O box, let's determine the absolute percentage of O alleles.
The absolute percentage of the population that has an type O allele is the square root of the population exhibiting that allele. To illustrate this, imaging the classic 50/50 population of a dominant and recessive allele. In that situation, only 25% of the population exhibits the recessive trait. And the square root of 0.25 is 0.5. The same principle applies for any ratio of recessive vs dominate traits. Since we see 46.24% showing that, the number with a type O allele will be sqrt(0.4624) = 0.68 = 68%.
Now we need to figure out the overall percentage of the population that are homozygous A. The population of those exhibiting the type A trait are a mixture of homozygous and heterozygous. There are 3 ways to exhibit the A trait. Having a genotype of AA, AO, or OA. So we can create the following equation.
PA = A^2 + 2OA
where
PA = Percent showing the trait
A = absolute percentage having the A allele
O = absolute percentage having the O allele
Substitute known values and solve.
PA = A^2 + 2OA
0.384 = A^2 + 2*0.68*A
0.384 = A^2 + 1.36A
0 = A^2 + 1.36A - 0.384
We now have a quadratic equation with A=1, B=1.36, and C=-0.384. Use the quadratic formula to get the roots of -1.6 and 0.24. The root of -1.6 doesn't make sense for this problem, so the absolute percentage of A alleles is 0.24
Since the total of all the alleles has to add to 1, that leaves us with B being 1 - 0.24 - 0.68 = 0.08
So for the total population we have A=0.24, B=0.08, and O=0.68. With those numbers we can calculate the percentage of the population that exhibits any specified blood type.
Type B = B*B + B*O + O*B
= 0.08*0.08 + 0.08*0.68 + 0.68*0.08
= 0.0064 + 0.0544 + 0.0544
= 0.1152
= 11.52%
Type AB = A*B + B*A
= 0.24*0.08 + 0.08*0.24
= 0.0192 + 0.0192
= 0.0384
= 3.84%
And since they all have to add to 100%, let's check that.
38.40 + 46.24 + 11.52 + 3.84 = 100</span>
Answer:
D. They live in freshwater, are free-living and reproduce sexually and asexually.
Explanation:
Most planarians are found in freshwater. Since they reproduce through fission, they reproduce asexually. However, since they are heteromorphic, they also reproduce sexually.