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nordsb [41]
3 years ago
7

In 2 mins., a conveyor belt moves 300 lbs. Of recycle aluminum from delivery truck to a storage area. A smaller belt moves the s

ame quantity of cans the same distance in 18 mins. If both belts are used, find how long it takes to move the cans to the storage area
Mathematics
1 answer:
kodGreya [7K]3 years ago
6 0

Answer:

1.8 minutes or 108 seconds

Step-by-step explanation:

The question tells us that the larger belt moves 300 lbs in 2 mins. And this is equal to 150 lb per minute

The question also tells us that a smaller belt moves the same quantity of 300 lbs in 18 mins. And this is equal to an average of 16.667 lb per min.

Both belts will move at a rate of 166.667 lb per min.

So it will take them 300 / 166.667 = 1.8 min or 108 s.

Therefore, the answer is 1.8 min

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Answer:

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Step-by-step explanation:

first use the y2-y1/x2-x1 formula then use y=mx+b after

plug in 2 for y2 and -1 for y1

plug in -5 for x2 and 5 for x1

\frac{2-(-1)}{-5-5}=

2+1=3

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-\frac{3}{10} is ur slope

_____________________

this is the y=mx+b formula *extra info ig*

i usually use the first point for this but u can use watever point u want

plug in 5 for x

plug in -1 for y

and plug -3/10 for m

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-1=-3/2+b

add -3/2 on both sides

-1+3/2=1/2

1/2=b and b is ur y-intercept

y=-3/10x+1/2

hope this helps

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Hope this helps.

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