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2 years ago

Last Question for me.

Mathematics

2 answers:

Oksana_A [137]2 years ago

8 0

Answer:

5 yards= 180 inches

6 yards =216 inches

if that's not what you're asking for then

5/6 yards=30 inches

iren2701 [21]2 years ago

5 0

Answer:

Question 2: 30 inches

Question 3: 4(1/5+2/3)

Step-by-step explanation:

Question 2 explanation: 6*6= 36 so 5/6 of 36 is 30 because you are taking away 1/6

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8th one answer this pls

GuDViN [60]

Answer:

terminating

Step-by-step explanation:

if the given fraction is terminating then prime factors of denominator should be 2^n x 5^m where m and n are whole number

5=1x5=2^0x5^1

so it is of form 2^nx5^m

8 0

2 years ago

What is the value of the expression below?<br> 64^4/6

bonufazy [111]

Answer:

64^(4/6) = 16

Step-by-step explanation:

8 0

3 years ago

Which system of equations is represented by the graph?

Arlecino [84]

Answer: C

Step-by-step explanation:

y = mx + b

To get ‘b’ look at the y intercepts.

Both y intercepts are 7 and - 1

For this problem it’s all you need, since the only equations with b being - 1 and 7 is C.

4 0

3 years ago

Lucy took three tests. If her median score was 86, her mean score was 87, and the range was 13, what were her three test scores?

sveticcg [70]

x+82+y
______________ =87
3
y-x=17
87,98, and 82.

3 0

3 years ago

The height of an object tossed upward with an initial velocity of 120 feet per second is given by the formula h = −16t2 + 120t,

AleksAgata [21]

Answer:

7.5 seconds

Step-by-step explanation:

$h = - 16 {t}^{2} + 120t \\ \because \: we \: have \: to \: find \: the \: time \: required \: \\ for \: the \: object \: to \: return to \: its \: \\ point \: of departure. \\ \therefore \: plug \: h = 0 \: in \: the \: given \: euation. \\ \therefore \: 0 = - 16 {t}^{2} + 120t \\ \therefore \:16 {t}^{2} - 120t = 0 \\ \therefore \:8t(2t - 15) = 0 \\ \therefore \:8t = 0 \: \: or \: \: (2t - 15) = 0 \\ \therefore \:t = \frac{0}{8} \: or \: t = \frac{15}{2} \\ \therefore \:t = 0 \: or \: t = 7.5 \\ \because \: t = 0 \: is \: not \: possible \\ \huge \purple{ \boxed{ \therefore \: t = 7.5 \: seconds}}$

Thus, the time required for the object to return to its point of departure is 7.5 seconds.

4 0

2 years ago