with that template in mind, let's see
so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
Let's draw the diagonals of the square. The square is being divided by 4 right triangles. & these right triangles are also isosceles (the diagonals of a square intercepts each other in the middle).
The area of each right triangle = (6 x 6) / 2 = 18 yard² & the 4 right triangles => 4x 18 = 72 yd²
Answer:
Step-by-step explanation:1
1/2 years which is 1 year and 5 months.
Explanation:
The formula for simple interest is
You can either substitute the given values first and the solve for
T, or you can transpose the formula to have
T as the subject.
T=100xSIPR
T=100 x 637.50
T=100×637.502500×17
T=1.5
As time is always in years, this means it was for
112 years which is 1 year and 5
months
Answer:
The correct answer is B- 21b+7bc
Step-by-step explanation:
7b(3+c)
(7b)(3+c)
(7b)(3)+(7b)(c)
21b+7bc
Answer:
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
6
2
−
5
−
4
=
0
6x^{2}-5x-4=0
6x2−5x−4=0
=
6
a={\color{#c92786}{6}}
a=6
=
−
5
b={\color{#e8710a}{-5}}
b=−5
=
−
4
c={\color{#129eaf}{-4}}
c=−4
=
−
(
−
5
)
±
(
−
5
)
2
−
4
⋅
6
(
−
4
)
√
2
⋅
6
Step-by-step explanation:
