Write the equation of a line passing through the points (5,-5) and (-5,-5)?
1 answer:
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So hmmm check the picture below
so... the vertex is "p" distance from the focus and the directrix, thus, the vertex is really half-way between both
in this case, 2 units up from the focus or 2 units down from the directrix, and thus it lands at 3,3
now, the "p" distance is 2, however, the directrix is up, the focus point is below it, the parabola opens towards the focus point, thus, the parabola is opening downwards, and the squared variable is the "x"
because the parabola opens downwards, "p" is negative, and thus, -2
now, let's plug all those fellows in then
so... the vertex is "p" distance from the focus and the directrix, thus, the vertex is really half-way between both
in this case, 2 units up from the focus or 2 units down from the directrix, and thus it lands at 3,3
now, the "p" distance is 2, however, the directrix is up, the focus point is below it, the parabola opens towards the focus point, thus, the parabola is opening downwards, and the squared variable is the "x"
because the parabola opens downwards, "p" is negative, and thus, -2
now, let's plug all those fellows in then
Given
Area of the regular pentagon is 6.9 cm².
Find out the perimeter of a regular pentagon
To proof
Formula
Area of regular pentagon is
As given in the question
area of regular pentagon = 6.9 cm²
now equating the area value with the area formula.
Now put
√5 = 2.24 ( approx)
put in the above equation
thus
a² = 4.01
a = √ 4.01
a = 2.0 cm ( approx)
As perimeter represented the sum of all sides.
i.e regular pentagon have five sides of equal length.
Thus
perimeter of the regular pentagon = 5 × side length
= 5 ×2.00
therefore the perimeter of the regular pentagon = 10cm
option c is correct
Hence proved