Answer:
-20
Step-by-step explanation:
when you solve: -7u-7=7, you get u= -2 and when you plug it in you get this equation 9(-2)-2=?
then you get -20
you combine like terms the (4v +5v) which comes to 9v and then you just divide by 9 to get v by itself. v=1
The enthalpy change (ΔH) for the reaction given the data from the question is –900.8 KJ
<h3>Data obtained from the question</h3>
- 4NH₃ + 5O₂ —> 6H₂O + 4NO
- Enthalpy of ammonia, NH₃ = –46.2 KJ
- Enthalpy of Oxygen = 0 KJ
- Enthalpy of water, H₂O = –241.8 KJ
- Enthalpy of nitric oxide, NO = 91.3 KJ
- Enthalpy change (ΔH) =?
<h3>How to determine the enthalpy change</h3>
ΔHrxn = ∑ΔH(products) - ∑ΔH(reactants)
ΔHrxn = ∑[H(H₂O) + H(NO)] - ∑[H(NH₃) + H(O₂)]
ΔHrxn = [(6 × –241.8) + (4 × 91.3)] – [(4 × –46.2) + (5×0)]
ΔHrxn = –1085.6 + 184.8
ΔHrxn = –900.8 KJ
Learn more about enthalpy change:
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Answer:
Im 47 and i have no idea
Step-by-step explanation:
thanks for 5 points
Answer:
4x + 12 = -4
4x = -16
x = -4
Step-by-step explanation:
Have a great day :)
