26% of 50
26/100 * 50
13
50 - 13 = 37
Answer: 8
Step-by-step explanation: hope this helps
6.4 is the answer hope this helps
Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
Answer:
13) 8.6
Step-by-step explanation:
To find the side length, use a trig function to solve for x.
You have the adjacent side and hypotenuse to the angle. Use the cosine function since its ratio is adjacent over hypotenuse.
This means Cos 52 = x / 14. Solve for x.
Cos 52 = x / 14
14* Cos 52 = x
8.6 = x
