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3 years ago

I will give brainliest to whoever answers this question. Also if you can please explain how you solved it I would appreciate it!

Mathematics

2 answers:

Allushta [10]3 years ago

6 0

Answer: 20

24 / 5 =4.8

4.8 x 5 = 19.8

i did the math wrong i think.

madreJ [45]3 years ago

3 0

It would be 25 ft because the person is 5 feet tall but the shadows only 4 ft :)

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Help pleaseeeeeeee.

Dmitry_Shevchenko [17]

Answer: 11x

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Explanation:

Let L be the length of rectangle B
There are two copies of L (along the top and bottom of the rectangle). The vertical pairs of sides are both 7x each.

For the triangle, we have three sides of 12x since this is an equilateral triangle. All three sides are congruent for any equilateral triangle.

The perimeter of the triangle is
P = s1+s2+s3
P = 12x+12x+12x
P = 36x

The perimeter of the rectangle is
P = 2*L+2*W
P = 2L+2*7x
P = 2L+14x

Since both perimeters are the same, this means
perimeter of triangle = perimeter of rectangle
36x = 2L+14x
36x-14x = 2L+14x-14x
22x = 2L
2L = 22x
2L/2 = 22x/2
L = 11x

So the length of the rectangle, in terms of x, is 11x. This is the final answer.

Note: if we knew the value of x, then we could find the numeric value of the length for the rectangle. But since we don't know x, we leave it as 11x.

7 0

3 years ago

The pyramid shown has a height of 14 inches and a base area of 60 in2. Find the volume of the pyramid.

Kamila [148]

Volume of pyramid is $280 in^{3}$ .

The pyramid has a height 14 inches and a base area of 60 in2.

What is volume?

Volume is a three - dimensional quantity that is used to measure the capacity of a solid shape.

Volume of the pyramid = $Area base$ X $\frac{height}{3}$

= $60.\frac{14}{3}$

= $280$ $in^{3}$

So the volume of pyramid = $280$ $in^{3}$

Learn more about the Volume visit:

https://brainly.in/question/609711

#SPJ1

8 0

2 years ago

A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears

marta [7]

Answer:

(a) The probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b) n = 28.09

Step-by-step explanation:

The random variable Yₙ is defined as the total numbers of dollars paid in n years.

It is provided that Yₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of Yₙ are:

$\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}$

(a)

For n = 20 the mean and standard deviation of Y₂₀ are:

$\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\$

Compute the probability that Y₂₀ exceeds 1000 as follows:

$P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z> 4.47)\\=1-P(Z$

**Use a z table for probability.

Thus, the probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b)

It is provided that P (Yₙ > 1000) > 0.99.

$P(Y_{n}>1000)=0.99\\1-P(Y_{n}$

The value of z for which P (Z < z) = 0.01 is 2.33.

Compute the value of n as follows:

$z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n} \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0$