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lawyer [7]
3 years ago
14

Find the unknown angle measures

Mathematics
2 answers:
Usimov [2.4K]3 years ago
8 0

Answer:

Step-by-step explanation:

ok so this is a vetical angle. so they are equal to 180. so if 1 measurement is found the other is the difference of 180 and that angle measeurement.

so y is the same as 110

and 180 - 110 is 70, so x and z are equal to 70.

i hope this helped you :)

Firlakuza [10]3 years ago
5 0

Answer:

y=110, x and z=70

Step-by-step explanation:

110 and y are congruent angles, so they both are 110 degrees.

both angles on the same side of the line always total 180 degrees,

so x and z must be 70.

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The number of potato chips in a bag is normally distributed with a mean of 74 and a standard deviation of 4. Approximately what
tangare [24]

Answer:  99.7 % of the bags contain between 62 and 86 potato chips.

Step-by-step explanation:

The standard deviation given is 4.

Find the difference between the given numbers and the mean,

74-62= 12 .  86-74=12

then  divide 12 by 4 to find the number of standard deviations:  12/4=3

Check a chart or diagram of the Gaussian Distribution to find that 99.7% of the samples lie within 3 standard deviations from the mean.

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3 years ago
One of the characteristics of legal English is _____.
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One of the characteristics of legal English is archaic English words.
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3 years ago
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The distribution of weights of potato chip bags filled off a production line is unknown. However, the mean is m=13.35 OZs and th
Nikitich [7]

Answer:

a) \mu_{\bar X} =13.35

e.none of the above

b) \sigma_{\bar X}= \frac{0.12}{\sqrt{36}}= 0.02

a.0.0200

c) z = \frac{13.32-13.35}{\frac{0.12}{\sqrt{36}}}= -1.5

P(\bar X< 13.32)= P(z

a.0.0668

d) z = \frac{13.30-13.35}{\frac{0.12}{\sqrt{36}}}= -2.5

z = \frac{13.36-13.35}{\frac{0.12}{\sqrt{36}}}= 0.5

P(13.30

c.0.6853

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(13.35,0.12)  

Where \mu=13.35 and \sigma=0.12

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Part a

\mu_{\bar X} =13.35

Part b

\sigma_{\bar X}= \frac{0.12}{\sqrt{36}}= 0.02

Part c

We want this probability:

P(\bar X< 13.32)

For this case we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got:

z = \frac{13.32-13.35}{\frac{0.12}{\sqrt{36}}}= -1.5

P(\bar X< 13.32)= P(z

Part d

We want this probability:

P(13.30

For this case we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got:

z = \frac{13.30-13.35}{\frac{0.12}{\sqrt{36}}}= -2.5

z = \frac{13.36-13.35}{\frac{0.12}{\sqrt{36}}}= 0.5

P(13.30

8 0
3 years ago
Please help ASAP I’ll mark brainlist
posledela

Answer:

d

Step-by-step explanation:

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