Question

Find the smallest zero for the function h(x) =4x squared -8x-60

Answer 1

Answer:

The smallest zero is $x=-3$

Step-by-step explanation:

The given function is

$h(x)=4x^2-8x-60$

To find the zeros of this function, we equate it to zero.

$\Rightarrow 4x^2-8x-60=0$

Dividing through by 4 gives

$x^2-2x-15=0$

We split the middle term to get;

$x^2-5x+3x-15=0$

Factor

$x(x-5)+3(x-5)=0$

Factor further to get;

$(x-5)(x+3)=0$

$(x-5)=0,(x+3)=0$

The zeros are

$x=5,x=-3$

The smallest zero is

$x=-3$