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adelina 88 [10]
3 years ago
15

Anna plans a business model to compete with two video stores, where she hopes to draw in customers from one store but not lose m

oney on the deal.
Movie Mania charges a subscription fee of $30 and an additional $5 per movie, x. Movie Time charges a subscription fee of $25 and an additional $6 per movie, x.

Based on this information, which system of inequalities could be used to determine how many movies need to be rented for a customer on Anna’s plan, y, to pay her more than they would at Movie Time, but less than they would at Movie Mania?
Mathematics
2 answers:
babymother [125]3 years ago
4 0
Let x be the number of movies, m(x) be how much Movie Mania charges and t(x) be how much Movie Time charges and a(x) be Anna's plan.

<span>Movie Mania charges a subscription fee of $30 and an additional $5 per movie
</span>
m(x)=30+5x 

<span>Movie Time charges a subscription fee of $25 and an additional $6 per movie

</span>t(x)=25+6x 

<span>How many movies need to be rented for a customer on Anna’s plan, y, to pay her more than they would at Movie Time, but less than they would at Movie Mania?

That's 

</span>t(y) < a(y) < m(y) 

Expanding it out,

25+6y< a(y) < 30+5y 
  
Is there any room there?

25+6y  <  30+5y

y < 5

There's no possible plan that will do what Anna wants for 5 or more movies, because in that domain Movie Time costs more than Movie Mania.  She can squeeze in there between 1 and 4 movies.

I write the answer as:

25+6y< a(y) < 30+5y 

shepuryov [24]3 years ago
4 0

Answer:

The person below is right but they just explained it alittle oddly so I'll clarify for them because it is correct :)

y<5x+30/x

y>6x+25/x

Step-by-step explanation:


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Draw the graph of the line that is parallel to y−3=1/3(x+2) and goes through the point (1,7).
horrorfan [7]

Answer:

Step-by-step explanation:

First find the slope of the given line.

y - 3 = 1/3(x+2)

y - 3 = (1/3)x + 2/3

y = (1/3)x + 2/3 + 3

y = (1/3)x + 11/3

Compare it with

y = mx + c

We get m = 1/3

As the parallel lines have same slope, the slope of the second line will also be m= 1/3

y = mx + c

y = (1/3)x + c

As this line goes through the point (1,7), substitute it in the equation:

7 = (1/3)1 + c

7 = 1/3 + c

c = 7 - 1/3

c = 21-1/3

c = 20/3

The equation of the line is found by substituting m = 1/3 and c = 20/3 into the general equation

y = mx + c

y = (1/3)x + 20/3

Graph of the equation is shown

5 0
3 years ago
Please solve!!!! Solve for x to the nearest tenth.
ki77a [65]

x = 11.2 this is rounded to the nearest tenth :)

6 0
2 years ago
Match each of the following complex numbers with its equivalent expression.
Yanka [14]

Answer:

Therefore

i^{110}=-1

i^{92}=1

i^{245}=i

i^{347}=-i

Step-by-step explanation:

Complex Number :

A complex number is a number that can be expressed in the form

a + bi

where a and b are real numbers, and

' i ' is called an imaginary number.

The value of i is given as

i=\sqrt{-1}

Squaring both the side we get

i^{2}=(\sqrt{-1})^{2}\\\therefore i^{2}=-1

Therefore on substituting we get

For i^110

i^{110}=(i^{2})^{55}=(-1)^{55}=-1

Similarly for i^92

i^{92}=(i^{2})^{46}=(-1)^{46}=1

Similarly for i^245

i^{245}=(i^{2})^{122}\times i=(-1)^{122}\times i=1\times i =i

Similarly for i^347

i^{347}=(i^{2})^{173}\times i=(-1)^{173}\times i=-1\times i =-i

Therefore

i^{110}=-1

i^{92}=1

i^{245}=i

i^{347}=-i

6 0
3 years ago
The area, a, of a square whose side length is n
svetlana [45]

Answer:

a*n=area

Step-by-step explanation:

3 0
3 years ago
What is the solution of -8/2y-8=5/y+4-7y+8/y^2-16 <br> y = –4 <br> y = –2 <br> y = 4 <br> y = 6
maria [59]
(-8)/(2y-8)=(5/(y+4))-7y+(8/(y^2-16))
(-4)/(y-4)=(5/(y+4))-7y+(8/(y+4)(y-4))
((-4)(y+4))/((y+4)(y-4))=((5(y-4))/(y+4)(y-4))-(7y(y+4)(y-4))/(y+4)(y-4))+(8/(y+4)(y-4))
(-4(y+4))=(5(y-4))-(7y(y+4)(y-4))+8
-4y-16=5y-20-(7y(y^2-16))+8
-4y-16=5y-20-7y^3+112y+8
-4y-16=117y-7y^3-12
-4=(121-7y^2)(y)
None of these choices would be equal to -4

4 0
3 years ago
Read 2 more answers
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